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sergey [27]
3 years ago
10

It takes a hose 2 minutes to fill a rectangular aquarium 12 inches long, 13 inches wide, and 14 inches tall. How long will it ta

ke the same hose to fill an aquarium measuring 32 inches by 34 inches by 35 inches?
Mathematics
1 answer:
rusak2 [61]3 years ago
8 0

Volume of the first aquarium =  (12" x 13" x 14") = 2,184 inches³

Volume of the second aquarium = (32" x 34" x 35") = 38,080 inches³

The second aquarium has (38,080 / 2,184) = 17.44 times as much
volume as the first aquarium has.

So it'll take the hose  17.44 times as long to fill the second one

                              =  (17.44) x (2 minutes)  =  34.9 minutes.
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Check the picture below.

the triangle has that base and that height, recall that A = 1/2 bh.

now as for the perimeter, you can pretty much count the units off the grid for the segment CB, so let's just find the lengths of AC and AB,

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&A&(~ 2 &,& 8~) 
%  (c,d)
&C&(~ 6 &,& 2~)
\end{array}~~~ 
%  distance value
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
AC=\sqrt{(6-2)^2+(2-8)^2}\implies AC=\sqrt{4^2+(-6)^2}
\\\\\\
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\\\\\\
AC=\sqrt{2^2\cdot 13}\implies AC=2\sqrt{13}

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&A&(~ 2 &,& 8~) 
%  (c,d)
&B&(~ 16 &,& 2~)
\end{array}\\\\\\
AB=\sqrt{(16-2)^2+(2-8)^2}\implies AB=\sqrt{14^2+(-6)^2}
\\\\\\
AB=\sqrt{196+36}\implies AB=\sqrt{232}\implies AB=\sqrt{4\cdot 58}
\\\\\\
AB=\sqrt{2^2\cdot 58}\implies AB=2\sqrt{58}

so, add AC + AB + CB, and that's the perimeter of the triangle.

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Hope this helps!

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