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Hunter-Best [27]
2 years ago
5

Evaluate the integral from negative infinity to infinity of xe^(x^(2)) dx

Mathematics
1 answer:
gogolik [260]2 years ago
8 0
\int{xe^{-x^2}}dx<span>

Let u=-x^2
du/dx=-2x
-du/2=x dx

</span>\int{xe^{-x^2}}dx=-1/2\int{e^u}du =- \frac{e^u}{2}+C=-\frac{e^{-x^2}}{2}+C

<span>When x approaches infinity (or minus infinity, since it is squared), e^(-x^2) approaches zero. So the answer is zero.</span>
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