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Nadya [2.5K]
3 years ago
14

Explain why the changes shown are physical change

Chemistry
1 answer:
Eva8 [605]3 years ago
5 0

Answer:

Because physical change are reversible change. we can reverse into the orginal effect.

please mark me as a brainlist..

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what is the strongest type of intermolecular forces present between a stearic acid molecule and a water molecule?
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Hydrogen bonding and dipole-dipole forces.
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What is the variable that is changed by
denpristay [2]

Answer:

b. independent/manipulated variable

Explanation:

Independent/manipulated variable - refers to the variable that is changed by the scientist or an experimenter. Only one variable that is independent is required to ensure a fair test in an excellent experiment. As the independent variable is being changed by an experimenter or scientist, data is being recorded simultaneously as they are collected.

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protein

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that the answer

8 0
3 years ago
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Arrange the following element, lithium, potassium, carbon and fluorine in increasing ionization energy
Juli2301 [7.4K]

Answer:

flourine(1681),carbon(1086),lithium(520) and potassium(419)

as we can see that the ionization energy of flourine is the highest than carbon than lithium and than potassium

Explanation:

i hope it will help you

4 0
3 years ago
Read 2 more answers
0.25 mol of nitric acid is used to make a 0.10 M nitric acid solution. How many grams of solute was used?
Yanka [14]

Answer:

15.75 grams of HNO3 was used and dissolved in 2.5 liters of solvent, to make a 0.10 M solution

Explanation:

Step 1: Data given

Nitric acid = HNO3

Molar mass of H = 1.01 g/mol

Molar mass of N = 14.0 g/mol

Molar mass O = 16.0 g/mol

Number of moles nitric acid (HNO3) = 0.25 moles

Molairty = 0.10 M

Step 2: Calculate molar mass of nitric acid

Molar mass HNO3 = Molar mass H + molar mass N + molar mass (3*O)

Molar mass HNO3 = 1.01 + 14.0 + 3*16.0

Molar mass HNO3 = 63.01 g/mol

Step 3: Calculate mass of solute use

Mass HNO3 = moles HNO3 * molar mass HNO3

Mass HNO3 = 0.25 moles * 63.01 g/mol

Mass HNO3 = 15.75 grams

15.75 grams of HNO3 was used and dissolved in 2.5 liters of solvent, to make a 0.10 M solution

7 0
3 years ago
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