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3 years ago

3. WEATHER On a cold January day,

Mathematics

1 answer:

erma4kov [3.2K]3 years ago

3 0

Answer: -9 + 21 = t t = 12°C.

Step-by-step explanation: For this problem lets have t be equal to the original temperature in the beginning of the day. The equation -9 + 21 = t represents this situation because it states that if we add the degrees that dropped to the current degrees it will give us our original degrees.

Solve.

-9 + 21 = t (Simply add -9 + 21) -9 + 21 = (+12)

12 = t

So, the original degrees in the beginning of the day was 12°C.

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#5 need help asap will give brainly

DerKrebs [107]

This might help

total surface area Stot = 42.5 ft2

lateral surface area Slat = 30 ft2

top surface area Stop = 6.25 ft2

bottom surface area Sbot = 6.25 ft2

but im thinking they would need 113.7 ft of rapping paper i many be totally wrong tho

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3 years ago

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What does the measure of B Equal?

defon

You have two triangles, ADC and ABC.
Sides AD and AB are congruent.
Sides DC and BC are congruent.
Side AC is congruent to itself.
By SSS, triangles ADC and ABC are congruent.

Corresponding parts of congruent triangles are congruent.
That means that angles DAC and BAC are congruent.
Angles DCA and BCA are congruent.

Since m<DAC = 32, then m<BAC = 32
Since m<DCA = 41, then m<BCA = 41.

Now you know the measures of two angles of triangle ABC.
The measures of the interior angles of a triangle add to 180.
You can find the measure of angle B.

m<BAC + m<B + m<BCA = 180

32 + m<B + 41 = 180

m<B + 73 = 180

m<B = 107

8 0

4 years ago

Joseph is pouring concrete for his new patio. The area of the patio is 25.2 square feet

lidiya [134]

Answer:

3.5ft

Step-by-step explanation:

A = L(W)

25.2 = 7.2(W)

3.5 = W

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2 years ago

How do I write 208,000,478 in expanded form

Rama09 [41]

200,000,000

8,000,000

478

all added together

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3 years ago

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Does the point (-4, 2) lie inside or outside or on the circle x^2 + y^2 = 25?

stiv31 [10]

Given equation of the Circle is ,

$\sf\implies x^2 + y^2 = 25$

And we need to tell that whether the point (-4,2) lies inside or outside the circle. On converting the equation into Standard form and determinimg the centre of the circle as ,

$\sf\implies (x-0)^2 +( y-0)^2 = 5 ^2$

Here we can say that ,

• Radius = 5 units

• Centre = (0,0)

Finding distance between the two points :-

$\sf\implies Distance = \sqrt{ (0+4)^2+(2-0)^2} \\\\\sf\implies Distance = \sqrt{ 16 + 4 } \\\\\sf\implies Distance =\sqrt{20}\\\\\sf\implies\red{ Distance = 4.47 }$

Here we can see that the distance of point from centre is less than the radius.

Hence the point lies within the circle .

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3 years ago

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