Help with algebra 3 please
1 answer:
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The question is incomplete! Complete question along with answer and step by step explanation is provided below.
Question:
An experiment to determine the most effective way to teach safety principles applied four different teaching methods. Some employees were given programmed instruction booklets and worked through the course at their own pace. Other employees attended lectures. A third group watched a television presentation, and a fourth group was divided into small discussion groups. A high of 10 was possible. A sample of five tests was selected from each group. The test grade results were:
Sample Programmed Instructions Lecture TV Group Discussions
1 6 8 7 8
2 7 5 9 5
3 6 8 6 6
4 5 6 8 6
5 6 8 5 5
At the 0.01 level, what is the critical value?
a. 5.29
b. 1.00
c. 3.24
d. 1.96
Answer:
The correct option is (a)
The critical value is 5.29
Step-by-step explanation:
To obtain the critical value, we need to perform a satistical test on the given data.
Since we are given data for four independent teaching methods to determine the most most effective way to teach safety principles, therefore, a one-way analysis of variance (ANOVA) may be used to get the critical value.
ANOVA:
The one-way analysis of variance (ANOVA) may be used to find out whether there is any significant difference between the means of two or more independent categories of data.
ANOVA in Excel:
Step 1:
In the data tab, select data analysis
Step 2:
Select "Anova single factor" from the analysis tools
Step 3:
Select the destination of input data in the "input range"
Step 4:
Select "columns" for the option "Group By"
Step 5:
Tick the option "labels in first row"
Step 6:
Set alpha = 0.01
Step 7:
Select the destination of output data in the "output options"
Output results:
Please refer to the attached results
As you can see in the output results, the critical value is 5.2922
Therefore, the correct option is (a)
