Answer:
Step-by-step explanation:
the formula for the circumference of a circle is 2rπ
the formula for the area of a circle is (r^2)π
the formula for the diameter of a circle is 2r
π=3.14
---------------------------------------------------------------
1. diameter =2r. since diameter=24, r=12
2. circumference=2rπ. since circumference = 314. 314=2rπ r=49.9746
3. circumference=2rπ area=(r^2)π
since r=7, circumference=14π=43.98229 since r=7, area is 49π=153.9380
4. Since the diameter is 20 the radius is 10. so just insert it into the formulas as before: circumference=20π=62.8318 and area=100π=314.15926
5. the formula for the diameter is 2r=d 2(18)=d, 36=d
6. 2rπ=circumference = 2(5)π=10π=31.415926
Hope that helps :)
Answer:
how many times larger? 4 times as large
Step-by-step explanation:
if the radius is half as big as the diameter and the diameter is half of the area
<u>r</u> x <u>r</u> = d
<u>d</u> x <u>d</u> = a
Answer:
$95.00
Step-by-step explanation:
gross=$617
tax deduction 15.4%
=617×0.154
=$95.00
(this shows the percent of people that would work over time on a regular basis out of the 30 people) 12/30= (40%) of the 30 said they would work overtime.
200×.4=80 employees of the 200 would have probably have said they would work overtime.
Answer:
111011
Step-by-step explanation:
Following the binary rule we can find the base 2 presentation of the decimal number 59.
To find the binary equivalence of 59 we use the sum of powers of 2.







Now we take our number and find out what the binary number will by taking our largest number closest to the number first.
59 = 32
We chose the number 32 since 64 will be a larger value than 59.
We then check how much we have to add to 32 to get 59.
59 = 32 + 27
We then look for the closest number to 27 in our powers of 2.
59 = 32 + 16
Now we check again for how much we need left to get a total of 59.
59 = 32 + 16 + 11
Now we repeat the same process of finding which value in the powers of 2 are closest to the number.
59 = 32 + 16 + 8 + 3
59 = 32 + 16 + 8 + 2 + 1
Now since we already have a total of 59, our binary number will be all the numbers present will have a value of 1 and the numbers now used will have a number of 0.
32 16 8 4 2 1
This can also be represented as:
2^5 2^4 2^3 2^1 2^0
Now we have to include the numbers that we skipped to get the total binary number.
32 16 8 4 2 1
1 1 1 0 1 1
This can be represented as:
59 = 32 16 + 8 + 0 + 2 + 1
1 1 1 0 1 1