Find the value of the csc 40° using your calculator. (I've been having a hard time with this, so it'd be helpful if anyone could
2 answers:
<span><u><em>The correct answer is: </em></u>
C 1.556.
<u><em>Explanation:</em></u>
This can be found by locating the csc button on your calculator. Typically it is located as the second option below the sin button as it is the inverse function.
If you cannot locate the csc button on your calculator, you can also use </span>
<span> as csc is its inverse.
Also, it is helpful to note that some calculators have both a degrees and a radians mode for trigonometric functions. You will need to make sure that you are in degrees in order to use a calculator to solve this. </span>
C 1.556.
<u><em>Explanation:</em></u>
This can be found by locating the csc button on your calculator. Typically it is located as the second option below the sin button as it is the inverse function.
If you cannot locate the csc button on your calculator, you can also use </span>
Also, it is helpful to note that some calculators have both a degrees and a radians mode for trigonometric functions. You will need to make sure that you are in degrees in order to use a calculator to solve this. </span>
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Solution
Hypotheses:
- The population mean is 132. In order to test the claim that the mean is 132, we should check for if the mean is not 132.
- Thus, the Hypotheses are:
Test statistic:
- The test statistic has to be a t-statistic because the sample size (n) is less than 30.
- The formula for finding the t-statistic is:
- Applying the formula, we have:
Critical value:
- The critical value t-critical, is gotten by reading off the t-distribution table.
- For this, we need the degrees of freedom (df) which is gotten by the formula:
- And then we also use the significance level of 0.1 and the fact that it is a two-tailed test to trace out the t-critical. (Note: significance level of 0.1 implies 10% significance level)
- This is done below:
- The critical value is 1.729
P-value:
- To find the p-value, we simply check the table for where the t-statistic falls.
- The t-statistic given is 1.5747. We simply check which values this falls between in the t-distribution table. It falls between 1.328 and 1.729. We can simply choose a value between 0.1 and 0.05 and multiply the result by 2 since it is a two-tailed test.
- However, we can also use a t-distribution calculator, we have:
- Thus, the p-value is 0.13183
Final Conclusion:
- The p-value is 0.13183, and comparing this to the significance level of 0.1, we can see that 0.13183 is outside the rejection region.
- Thus, the result is not significant and we fail to reject the null hypothesis
