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VladimirAG [237]
2 years ago
14

Find the value of the csc 40° using your calculator. (I've been having a hard time with this, so it'd be helpful if anyone could

explain how I could solve this, please)
1.342
0.745
1.556
0.643
Mathematics
2 answers:
SCORPION-xisa [38]2 years ago
7 0
<span><u><em>The correct answer is: </em></u>
C 1.556.

<u><em>Explanation:</em></u>
This can be found by locating the csc button on your calculator. Typically it is located as the second option below the sin button as it is the inverse function.
If you cannot locate the csc button on your calculator, you can also use </span>\frac{1}{sin(40)}<span> as csc is its inverse.

Also, it is helpful to note that some calculators have both a degrees and a radians mode for trigonometric functions. You will need to make sure that you are in degrees in order to use a calculator to solve this. </span>
Nataliya [291]2 years ago
3 0

Answer:

Option C is the correct answer.

Step-by-step explanation:

The question is to find the value of cosec 40°.

We know that cosecθ = 1/sinθ

Most of the calculators won't be having cosec function, they will be having only sin function.

So for calculating cosec 40° first find the value of sin 40° and then calculate 1/sin 40° to get the value of cosec 40°.

We have

                     sin 40° = 0.642

                    1/sin 40° = 1.556

Option C is the correct answer.

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yanalaym [24]

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Step-by-step explanation:

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3 0
3 years ago
Do the equations y = -6x +4 and y = 4x + 6 have one solution, no solution, or infinitely many solutions
Black_prince [1.1K]

Answer:

One solution

Step-by-step explanation:

We know there is only one solution because the lines do not have the same slope, nor are they the exact same line.

So we know they must have just one solution.

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6 0
2 years ago
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Assume that a simple random sample has been selected from a normally distributed population. State the hypotheses, find the test
BaLLatris [955]

Solution

Hypotheses:

- The population mean is 132. In order to test the claim that the mean is 132, we should check for if the mean is not 132.

- Thus, the Hypotheses are:

\begin{gathered} H_0:\mu=132 \\ H_1:\mu\ne132 \end{gathered}

Test statistic:

- The test statistic has to be a t-statistic because the sample size (n) is less than 30.

- The formula for finding the t-statistic is:

\begin{gathered} t=\frac{\bar{X}-\mu}{\frac{s}{\sqrt{n}}} \\  \\ where, \\ \bar{X}=\text{ Sample mean} \\ \mu=\text{ Population mean} \\ s=\text{ Standard deviation} \\ n=\text{ Sample size} \end{gathered}

- Applying the formula, we have:

\begin{gathered} t=\frac{137-132}{\frac{14.2}{\sqrt{20}}} \\  \\ t=\frac{5}{3.1752} \\  \\ t\approx1.5747 \end{gathered}

Critical value:

- The critical value t-critical, is gotten by reading off the t-distribution table.

- For this, we need the degrees of freedom (df) which is gotten by the formula:

\begin{gathered} df=n-1 \\ df=20-1=19 \end{gathered}

- And then we also use the significance level of 0.1 and the fact that it is a two-tailed test to trace out the t-critical. (Note: significance level of 0.1 implies 10% significance level)

- This is done below:

- The critical value is 1.729

P-value:

- To find the p-value, we simply check the table for where the t-statistic falls.

- The t-statistic given is 1.5747. We simply check which values this falls between in the t-distribution table. It falls between 1.328 and 1.729. We can simply choose a value between 0.1 and 0.05 and multiply the result by 2 since it is a two-tailed test.

- However, we can also use a t-distribution calculator, we have:

- Thus, the p-value is 0.13183

Final Conclusion:

- The p-value is 0.13183, and comparing this to the significance level of 0.1, we can see that 0.13183 is outside the rejection region.

- Thus, the result is not significant and we fail to reject the null hypothesis

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nika2105 [10]
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