Answer:
y = 3/4x - 9/8
Then read explanation and see here with 2 coordinates would make
if 3/4 = -6 then 1 = -8
y = -6x + c
-6 / 3/4 + 9/8 / - 0.5 = -2.25
therefore c = -2.25
y = -6x - 2.25
y = -6x - 9/4 and again 9/4 can be found easily if round up fraction decimal to 225/100 and divide by 4
Step-by-step explanation:
C1) (0.5 , -0.75)
C2) ( 1. -3.75)
y = mx + c
-3.75 - - 0.75 / 1 - 0.5 = -3.75 + 0.75 / 0.5
= -3 / 0.5 = m
m = -6
y = -6x + c
then this works given just one coordinate to solve for 1 or 2 sets given points
y - y1 = mx+c
y - - 0.75 = 0.75 (x - x1)
y + 0.75 = 0.75 (x - 0.5)
y + 0.75 = 0.75x - 0.375
y = 0.75 - 0.75 = 0.75x( - 0.375 - 0.75)
y = 0.75x -1.125
y = 3/4x - 9/8 as common denominators of 1125/1000 is 9/8 as we divide by 125 into the fraction as we start at 250 and check its half just like when finding common denominators we 1/4 the lower number and see if we can find its half or its double etc with the other num er as first step for 3sf numbers.
A) -6
b) 49
c)23
d)-47
e)73
f)20
g)131
h)-79
i)48
j) 68
Bagels 6x12=72
apples 8x9=72
cookies 12x6=72
juice 9x8=72
72/4 kids is 18 lunches
Step-by-step explanation:
Hey there!
It is said we need to find the unit rate.
What we can do is apply Unitary Method.
3 minutes = 42 push ups
1 minute = 
<u>So, 12 push ups per minute is the unit rate.</u>
In 5 minutes, he will do 12×5 = <u>60 push ups!</u>
Hope it helps :)
Answer:
The revenue depends on the number of people n that purchases tickets, knowing that each ticket costs $30.00, the total revenue will be:
f(n) = $30.00*n
Now, we also know that the stadium is capable of seating a maximum of m fans, so the maximum possible value for n is m.
Now, for the function f(n), we have that:
The domain is the set of the possible values of n
The range is the set of the possible values of f(n).
We want to find the domain.
First, the minimum possible value of n is 0, the case where nobody purchases a ticket.
The maximum possible value of n is m, this is the case where the stadium is full.
Then the domain will be:
D= {n,m ∈ Z, 0 ≤ n ≤ m}
Where we imposed that n must be an integer number because n represents a whole quantity.
