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Anna007 [38]
3 years ago
7

Explain why an equilateral triangle is also isosceles.

Mathematics
1 answer:
Pavel [41]3 years ago
5 0
An isosceles triangle needs to have two equal sides and an equilateral triange has all three sides are equal which also means two sides are equal.
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$68 for 812 hour find the unit rate
Alchen [17]

Answer:

$8 per hour

Step-by-step explanation:

The unit rate is $ per hour

Divide the amount by 8 \frac{1}{2} = 8.5 hours

$68 ÷ 8.5 = $8 per hour

4 0
3 years ago
Read 2 more answers
5x + 50 = 100<br> What is x?
vfiekz [6]

Answer:

x = 10

Step-by-step explanation:

5x + 50 = 100

=> 5x = 100 - 50

=> 5x = 50

=> x = 10

Hoped this helped.

8 0
3 years ago
A local parking garage charges $5 for the first hour and $1.25 for each additional hour. Write an equation in function notation
JulijaS [17]
Y=5+1.25x x=6 Meaning at 6 hours it would cost $12.50
4 0
3 years ago
Rewrite the decimal fraction as a decimal number.
Sergio039 [100]

Answer:

8.025

Step-by-step explanation:

If you count the zeros in 1000, it's three. Count three starting from the back of 25. Add 0 in front of 25 to make it a three digit number. You then put the decimal point with the whole number.

7 0
4 years ago
How to solve for first derivative?? I have two questions, one where I have the answer, however one where I don’t. The format of
rjkz [21]

Answer:

Q1: f'(x) = (-6x^8 + 2x^4 + 4)(48x^7) + (6x^8)(-48x^7 + 8x^3)

Q2: f'(x) = (6x^4)(18x^2 - 54x^8) + (6x^3 - 6x^9 + 3)(24x^3)

Step-by-step explanation:

The derivative of the product of two functions is:

f(x) = v(x)u(x)

f'(x) = v(x)u'(x) + u(x)v'x)

The derivative is the product of the first function and the derivative of the second function added to the product of the second function and the derivative of the first function.

Q1: The function you are given is:

f(x) = 6x^8(-6x^8 + 2x^4 + 4)

You can think of that function as the product of functions

u(x) = 6x^8 and v(x) = -6x^8 + 2x^4 + 4

We first find the derivatives of functions u and v:

u'(x) = 48x^7 and v'(x) = -48x^7 + 8x^3

Now we follow the rule above:

f'(x) = v(x)u'(x) + u(x)v'x)

f'(x) = (6x^8)(-48x^7 + 8x^3) + (-6x^8 + 2x^4 + 4)(48x^7)

Use the commutative property to change the order of the sum.

f'(x) = (-6x^8 + 2x^4 + 4)(48x^7) + (6x^8)(-48x^7 + 8x^3)

This is the solution you have.

Q2: The function you are given is:

f(x) = 6x^4(6x^3 - 6x^9 + 3)

You can think of that function as the product of functions

u(x) = 6x^4 and v(x) = 6x^3 - 6x^9 + 3

We first find the derivatives of functions u and v:

u'(x) = 24x^3 and v'(x) = 18x^2 - 54x^8

Now we follow the rule above:

f'(x) = v(x)u'(x) + u(x)v'x)

f'(x) = (6x^4)(18x^2 - 54x^8) + (6x^3 - 6x^9 + 3)(24x^3)

5 0
3 years ago
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