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2 years ago

8

8 black balls and 7 red balls in an urn. 5 are withdrawn without replacement. What is probability exactly 2 black balls will be

drawn?

1 answer:

densk [106]2 years ago

6 0

6 black balls to 4 red balls

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Solve the following problems. Reduce your answers to their simplest form. a. 13⁄41 + 27⁄82 b. 3 5⁄24 + 6 7⁄24 + 4 9⁄24 c. 5 2⁄3

KATRIN_1 [288]

<span>13⁄41 + 27⁄82 = 26/82 + 27/82 = 53/82

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Suppose that contamination particle size (in micrometers) canbe modeled as

asambeis [7]

Answer:

c) 2

d) 0.96

Step-by-step explanation:

We are given the following in the question:

$f(x) = 2x^{-3}, x > 1\\~~~~~~~= 0, x \leq 1$

a) probability density function.

$\displaystyle\int^{\infty}_{\infty}f(x) dx = 1\\\\\displaystyle\int^{\infty}_{-\infty}2x^{-3}dx = 1\\\\\displaystyle\int^{\infty}_{1}2x^{-3}dx\\\\\Rightarrow \big[-x^{-2}\big]^{\infty}_1\\\\\Rightarrow -(0-1) = 1$

Thus, it is a probability density function.

b) cumulative distribution function.

$P(X$

c) mean of the distribution

$\mu = \displaystyle\int^{\infty}_{-\infty}xf(x) dx\\\\\mu = \int^{\infty}_12x^{-2}dx\\\\\mu = (-\frac{2}{x})^{\infty}_{1}\\\\\mu = 2$

d) probability that the size of random particle will be less than 5 micrometers

$P(X$

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