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3 years ago

Help me with these questions. If you can put on a separate piece of paper then send it. With the work shown out

Mathematics

1 answer:

natta225 [31]3 years ago

3 0

All you need to do is balqnce the equations so that you can do simultaneous equwtions

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Which inequality best represents the range of the relation shown below?

NikAS [45]

Answer:C

Step-by-step explanation:

7 0

3 years ago

Find volume with full working out pls asap

ZanzabumX [31]

Answer:

868 m³

Step-by-step explanation:

Volume = Difference of cones

V = ⅓(pi×r²h)

Volume of cone with base Circle O:

h = 8.2+8.2 = 16.4 m

V1 = ⅓(pi×7.6²×16.4)

V1 = 991.97

Volume of cone with base Circle A:

V2 = ⅓(pi×3.8²× 8.2)

V2 = 124 m³

Volume = V1 - V2

991.97 - 124 = 868 m³

6 0

3 years ago

During the month of February, Fabulous Feet Shoe Mart sold 30 pairs of red loafers. After an ad campaign to boost sales, they so

Natalija [7]

Answer:

20%

Step-by-step explanation:

To find the percent increase lets first find the increase.

36-30 = 6

Now divide the increase by the original amount

6/30 = 1/5 = 20%

5 0

3 years ago

ALGEBRA QUESTION PLS HELPS

cluponka [151]

The value of x is –7.

Solution:

Given expression:

$$\left(\frac{1}{x+3}+\frac{6}{x^{2}+4 x+3}\right) \cdot \frac{x+3}{x+1}$

Let us factor $x^2+4x+3$ .

$x^2+4x+3=(x+1)(x+3)$

Substitute this in the fraction.

$$\left(\frac{1}{x+3}+\frac{6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}$

To make the denominator same, multiply and divide the first term by (x +1).

$$\left(\frac{(x+1)}{(x+1)(x+3)}+\frac{6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}$

Denominators are same, you can add the fractions.

$$\left(\frac{x+1+6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}$

$$\frac{x+7}{(x+1)(x+3)} \cdot \frac{x+3}{x+1}$

Cancel the common term in the numerator and denominator.

$$\frac{x+7}{x+1} \cdot \frac{1}{x+1}$

Multiply the fractions.

$$\frac{x+7}{(x+1)^2}$

$$\frac{x+7}{x^2+2x+1}$

The expression is simplified to one rational expression.

Suppose the expression is equal to 0.

$$\frac{x+7}{x^2+2x+1}=0$

Do cross multiplication.

$${x+7}=0\times (}{x^2+2x+1})$

Any number or variable multiplied by 0 gives 0.

$${x+7}=0$

Subtract 7 from both sides of the equation.

$${x+7-7}=0-7$

x = –7

The value of x is –7.

7 0

2 years ago

Luke is 5 years younger than 3 times in Sydney's age in the situation what does 3s represnt

Fudgin [204]

3s is 3 times sydneys age. so the equation would be 3s-5

8 0

3 years ago