1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Simora [160]
3 years ago
13

3(t + 4) - 2(2t + 3)= -4

Mathematics
2 answers:
Naddik [55]3 years ago
6 0

Answer:

t = 10

Step-by-step explanation:

hope that helps

MatroZZZ [7]3 years ago
3 0

Answer:

T=10

Step-by-step explanation:

3(t + 4) - 2(2t + 3)= -4

3t+12-4t-6=-4

-t+6=-4

-t=-10

t=10

You might be interested in
Plz hurry more questions on the way
Scrat [10]
The answer is A, I’m pretty sure
7 0
3 years ago
Read 2 more answers
Can someone pls answer this question what is 12 +z=15
ANTONII [103]

12 + z = 15


12 - 12 + z = 15 - 12


0 + z = 3


z = 3


3 0
3 years ago
Read 2 more answers
Find the percent increase. Round to the nearest percent. From 13 friends to 16 friends
larisa86 [58]

The percentage increase; you'll need to take the new value and subtract it by the old value.

16 - 13 = 3

Next, you'll divide 3 by the original value.

3 ÷ 13 = 0.23

And multiply by 100

The percentage increase of friends is 23%

8 0
3 years ago
MATH 15 POINTS, HELP
7nadin3 [17]
Statement 3: tri egc = tri egb
statement 4: tri ebc is equilateral.
reason 5: equilateral triangles have equal angles
4 0
3 years ago
A circle has centre (3,0) and radius 5. The line y = 2x + k intersects the circle in two points. Find the set
lara [203]

A circle with center (3,0) and radius 5 has equation

(x-3)^2+y^2=25 \iff x^2 + y^2- 6 x  = 16

If we substitute y=2x+k in this equation, we have

x^2+(2x+k)^2-6x=16 \iff 5x^2+(4k-6)x+k^2-16=0

This equation has two solutions (i.e. the line intersects the circle in two points) if and only if the determinant is greater than zero:

\Delta=b^2-4ac=(4k-6)^2-4\cdot 5\cdot (k^2-16)>0

The expression simplifies to

-4 (k^2 + 12 k - 89)>0 \iff k^2 + 12 k - 89

The solutions to the associated equation are

k^2 + 12 k - 89=0 \iff k=-6\pm 5\sqrt{5}

So, the parabola is negative between the two solutions:

-6-5\sqrt{5}

8 0
3 years ago
Other questions:
  • What is 2 and 4?? would they be independent or dependent
    6·1 answer
  • Please help!!! I will medal and thanks:)
    7·2 answers
  • A triangle with two congruent angles can never be scalene true or false
    15·2 answers
  • 50 POINTS AND BRAINLIEST! What is the area of this figure?
    10·2 answers
  • The picture has the 2 questions
    5·1 answer
  • What does e represent in e/2=3
    11·1 answer
  • Find the measure of angle x in the figure attached<br><br> A) 35°<br> B) 48°<br> C) 69°<br> D) 78°
    8·1 answer
  • Multiply3x-4/2x+3×x+1/3x2​
    6·1 answer
  • Please help on this i dont get it at all!
    14·1 answer
  • Find the missing side, round the nearest tenth
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!