Answer:
0.79 sec
Step-by-step explanation:
Given there is a tool at the top of the building which is dropped by a worker and it follows the following equation at every instant of time .
![h(t)=-16t^{2} +h_{0}](https://tex.z-dn.net/?f=h%28t%29%3D-16t%5E%7B2%7D%20%2Bh_%7B0%7D)
where ![h_{0} =10 feet](https://tex.z-dn.net/?f=h_%7B0%7D%20%3D10%20feet)
We know that this height is measured from the base of the building which means that when the tool reaches the bottom of the building it has h = 0 feet.
Let this be done at time t
h(t) = 0
![-16t^{2} +10=0](https://tex.z-dn.net/?f=-16t%5E%7B2%7D%20%2B10%3D0)
![t^{2} =\frac{10}{16}](https://tex.z-dn.net/?f=t%5E%7B2%7D%20%3D%5Cfrac%7B10%7D%7B16%7D)
![t=\frac{\sqrt{10} }{4}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B%5Csqrt%7B10%7D%20%7D%7B4%7D)
t = 0.79 sec
Therefore the total time taken by the tool to reach the bottom of the building is 0.79 sec.
Answer:
- f(x) = 5x + 10 and g(x) = 0.2x -2
- f(x) = 1/4x -1 and g(x) = 4x + 4
Step-by-step explanation:
f and g will be inverses if f(g(x)) = x.
A — f(g(x)) = 5(0.2x -2) +10 = x -10 +10 = x . . . . . inverses
B — f(g(x)) = (±√x+3)^2 +3 = x ±6√x +9 +3 ≠ x . . . . . not inverses
(even if it is g(x) = ±√(x+3), the functions are still not inverses)
C — 1/2(2x -7) +7 = x -7/2 +7 = x +7/2 ≠ x . . . . . not inverses
D — 1/4(4x +4) -1 = x +1 -1 = x . . . . . inverses
Ouch, kinda crippled w/o answer choices.
But with my calculating, i've made it out to be <span>92.07 %
Please do respond & rate based on my accuracy.
-Feeling confident-
</span>
Answer:
vas tu trou Vera sure mention la responses correct
Answer:
BC =26
Step-by-step explanation:
AB is to be doubled in order to equal AC. 6x-2 = 8x-20. X=9
Since B is the midpoint BC=AB, so both sides would be equal to 26