Answer:
High specific heat capacity.
Explanation:
The specific heat capacity of water is the quantity of heat energy needed to raise 1 kg of water by one degree.
The high specific heat capacity of water is due to high hydrogen bonds which holds water molecules together, preventing their free movements.Therefore, large amount of energy is needed to raise water temperature. The hydrogen bonds also enabled water to store energy.
This features of water makes, plasma resistant to fluctuations in body and environmental temperature, and allows biochemical reactions to occurs at relatively constant rate.
Answer:
BB and bb
Explanation:
You can solve this by conceptually undoing the punnet square. Each one of the children have a dominant allele (B) and a recessive allele (b). This means that all of them will show the dominant trait. So by that, we know one parent must possess BB and the other one must be bb.
hope this helps :)
The answer is D) <span>Calculate the probability of a child having either sickle-cell anemia or cystic fibrosis if parents are each heterozygous for both.
The addition rule is used to calculate the probability of one of the events from multiple pathways. If you want that only one of the events happens, you will use the addition rule. In a case when you want to calculate the possibility of a child having EITHER sickle-cell anemia OR cystic fibrosis, you will use THE ADDITION RULE.
For example, in statement B) you will not use this rule because there is no either/or, but both/and. In case, B) you would use the multiplication rule.</span>
A human body consists of trillions of cells organized in a way that maintains distinct internal compartments. These compartments keep body cells separated from external environmental threats and keep the cells moist and nourished.
Answer:
100% black
Explanation:
<em>The allele for black is dominant over that of the grey fur.</em>
Let B represents the allele for black color and b for grey color.
Homozozygous black rabbit will have the genotype: BB
Heterozygous black rabbit will have the genotype: Bb
If the two are crossed;
BB x Bb
Offspring: BB, Bb, BB, and Bb = 2BB and 2Bb
2BB = Black fur
2Bb = Black fur (heterozygous)
Both BB and Bb offspring are black phenotypically.
<em>Hence, all the offspring will appear black, a phenotypical ratio of </em><em>100% black.</em>
