Question

Sin(-180° + θ) = ________

Answer 1

Answer:

$\sin\left(-180^o+\theta\right)=-\sin\left(\theta\right)$

Step-by-step explanation:

We need to find the value of $\sin(-180^o+ \theta)$

So let's apply formula

$\sin\left(A+B\right)=\sin\left(A\right)\cos\left(B\right)+\sin\left(B\right)\cos\left(A\right)$

$\sin\left(-180^o+\theta\right)=\sin\left(-180^o\right)\cos\left(\theta\right)+\sin\left(\theta\right)\cos\left(-180^o\right)$

$\sin\left(-180^o+\theta\right)=0\cdot\cos\left(\theta\right)+\sin\left(\theta\right)\cdot\left(-1\right)$

$\sin\left(-180^o+\theta\right)=0-\sin\left(\theta\right)$

$\sin\left(-180^o+\theta\right)=-\sin\left(\theta\right)$