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OLEGan [10]
3 years ago
14

What is quadratic inequality

Mathematics
2 answers:
worty [1.4K]3 years ago
6 0

Answer:

☆<《<em><u>HOPE IT WILL HELP YOU</u></em><em><u> </u></em>》>☆

Step-by-step explanation:

quadratic equation is an equation of second degree that use an initially sign in stand of equal sign the solution of quadratic inquality always give the two root

vodomira [7]3 years ago
4 0

Answer:

<h3>It's inequality where you have the unknown with exponent 2 and no higher exponents.</h3>

For example:

                     x^2-5x+35x^2+1\\\\4x^2-1\geqslant0\\\\5\leqslant-10x^2

These are NOT quadratic inequalities:

                                                               x^3-5x+35x^5+1\\\\4x^2-x^6\geqslant0\\\\5\leqslant-10x

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How mang feet are in 3.76 km? Show ur solution
Zina [86]

formula: multiply the value in kilometers by the conversion '3280. 839895

Step-by-step explanation:

so, 3.76 kilometers =3.6× 3280. 839895 =12335.96 feets

3 0
3 years ago
I need some help with this math problem
gizmo_the_mogwai [7]

Step-by-step explanation:

15 long

12 wide

10 high

we need all for walls

hight times length two times ( these are the front and back walls )

hight times width two times ( These are the side walls )

the roof is

width times length (only once as only the ceiling)

same measurement as the floor

can you work it out with that

please mark brainiest

8 0
3 years ago
A person 6ft tall stands 10ft from point P directly beneath a lantern hanging 30 ft above the ground. The lantern start to fall,
xxMikexx [17]

Answer:

\frac{dL}{dt}=30 \frac{ft}{s}

Step-by-step explanation:

In order to solve this it is always a good idea to start by drawing a diagram of the situation (See attached picture).

From the diagram we can see that we are dealing with similar triangles. We can use similar triangles to build an equation that relates the length of the shadow with the height of the lamp, so we get:

\frac{L}{6}=\frac{10+L}{h}

the height of the lamp can be found by subtracting the 16t^{2} distance the lamp falls in a given time t from the original 30ft the lamp was located at.

So the equation will now lok like this:

\frac{L}{6}=\frac{10+L}{30-16t^{2}}

So now we can solve the equation for L, we can start by multiplying by the LCD SO WE GET:

L(30-16t^{2})=6(10+L)

next, we can distribute the right side of the equation so we get:

L(30-16t^{2})=60+6L

and subtract 6L from both sides so we get:

L(30-16t^{2})-6L=60

and factor L, so we get:

L(30-16t^{2}-6)=60

and solve for L:

L=\frac{60}{24-16t^{2}}

now, we can differentiate this equation by using the chain rule, so we get:

dL=-\frac{60}{(24-16t^{2})^{2}}(-32t)dt

which can be simplified to:

\frac{dL}{dt}=\frac{1920t}{(24-16t^{2})^{2}}

and now we can substitute t for 1s so we get:

\frac{dL}{dt}=\frac{1920(1)}{(24-16(1)^{2})^{2}}

\frac{dL}{dt}=30 \frac{ft}{s}

7 0
3 years ago
Heidi must correctly answer at least 80% of the questions on an exam to advance to the next
Oduvanchick [21]
Given:
must correctly answer 80% of the questions
correctly answered questions = 26
incorrectly answered questions = 4
unanswered questions = 15

Total questions = 26 + 4 + 15 = 45

45 * 80% = 36 required correctly answered questions.

36 - 26 = 10

Out of 15 remaining questions, 10 questions must be correctly answered for Heidi to advance to the next level.
3 0
4 years ago
I know that the answer isn't x=0. Please help.
WITCHER [35]

(2x+8)/6=1/3(x+4)

3(2x+8)=6(x+4)

6x+24=6x+24.

0=0.

∴There are no real solutions.

8 0
4 years ago
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