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3 years ago

Identify the transformation(s) where the image has the opposite orientation as the preimage.

Mathematics

2 answers:

Dmitry_Shevchenko [17]3 years ago

6 0

<span>glide reflection and reflection</span>

Afina-wow [57]3 years ago

3 0

Answer: C) glide reflection and reflection

Step-by-step explanation:

An opposite transformation is a rigid transformation that changes the orientation of a figure.

There are two types of opposite transformations : Reflections and glide reflections .

Therefore, the transformations where the image has the opposite orientation as the pre-image are glide reflection and reflection.

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Trapezoid WKRP was translated 4 units to the left and 5 units up on a coordinate grid to create trapezoid W’K’R’P’. Which rule d

saw5 [17]

The rule used to describe this transformation is (x, y)→(x - 4, y + 5)

<h3>Transformation</h3>

Transformation is the movement of a point from its initial location to a new location. Types of transformation are<em> rotation, reflection, translation and dilation.</em>

If a point A(x, y) is translated a units left and b units up. the new point is at A'(x - a, y + b)

Given Trapezoid WKRP was translated 4 units to the left and 5 units up on a coordinate grid to create trapezoid W’K’R’P’. The rule is given by:

(x, y)→(x - 4, y + 5)

The rule used to describe this transformation is (x, y)→(x - 4, y + 5)

Find out more on Transformation at: brainly.com/question/1462871

3 0

2 years ago

PLEASE HELP ME....ASAP

olchik [2.2K]

Answer:

1681 for area of <em>rectangle</em>

7 0

2 years ago

Please please help me

Gekata [30.6K]

Answer:

$\large\boxed{\dfrac{\boxed{8}}{81}}$

Step-by-step explanation:

$\text{If}\ a_1,\ a_2,\ a_3,\ a_4,\ ...,\ a_n\ \text{is the geometric sequence, then}\\\\\dfrac{a_2}{a_1}=\dfrac{a_3}{a_2}=\dfrac{a_4}{a_3}=...=\dfrac{a_n}{a_{n-1}}=constant=r-\text{common ration}.\\\\\text{We have}\ \dfrac{1}{2},\ \dfrac{1}{3},\ \dfrac{2}{9},\ \dfrac{4}{27},\ ...\\\\\dfrac{\frac{1}{3}}{\frac{1}{2}}=\dfrac{1}{3}\cdot\dfrac{2}{1}=\dfrac{2}{3}\\\\\dfrac{\frac{2}{9}}{\frac{1}{3}}=\dfrac{2}{9}\cdot\dfrac{3}{1}=\dfrac{2}{3}\\\\\dfrac{\frac{4}{27}}{\frac{2}{9}}=\dfrac{4}{27}\cdot\dfrac{9}{2}=\dfrac{2}{3}$

$\bold{CORRECT}\\\\\dfrac{x}{\frac{4}{27}}=\dfrac{2}{3}\qquad\text{multiply both sides by}\ \dfrac{4}{27}\\\\x=\dfrac{2}{3}\cdot\dfrac{4}{27}\\\\x=\dfrac{8}{81}$

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2 years ago

Does the point (6, 0) satisfy the equation y = x2?

shtirl [24]

Replace x in the equation with the x value of the point (6) and solve. If it equals the y value (0) it is a solution if it noes not equal (0) it is not a solution.

Y = 6^2 = 36

36 is not 0 so (6,0) is not a solution

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Ipatiy [6.2K]

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