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sleet_krkn [62]
3 years ago
9

Students who have completed a speed reading course have reading speeds that are normally distributed with a mean of 950 words pe

r minute and a standard deviation equal to 220 words per minute. Based on this information, what is the probability of a student reading at more than 1400 words per minute after finishing the course
Mathematics
1 answer:
Free_Kalibri [48]3 years ago
3 0

Answer:

0.020405

Step-by-step explanation:

We solve this question, using z score formula.

z-score formula =

z = (x-μ)/σ,

where x is the raw score

μ is the population mean

σ is the population standard deviation.

From the above question:

x = 1400, μ = 950, σ = 220

z = 1400 - 950/220

z = 2.04545

Determining the probability from Z-Table:

P(z = 2.04545) = P(x<1400) = 0.97959

P(x>1400) = 1 - P(x<1400)

= 1 - 0.97959

= 0.020405

Therefore, the probability of a student reading at more than 1400 words per minute after finishing the course is 0.020405

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Consider the following system of equations 2x+3y=45 x+y=10 what is the x value of the solution for this system
scZoUnD [109]
2x + 3y = 45
x + y = 10......y = 10 - x

2x + 3(10 - x) = 45
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-x + 30 = 45
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x = -15 <====

and y = 25
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3 years ago
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163. The sum of an odd number and an even number is --
crimeas [40]

Answer:

C

Step-by-step explanation:

I would say C because,

Even + Even = Even.

Odd + Odd = Odd.

So simply, you can't have an even number if you add it to a odd.

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Step-by-step explanation:

You know that the given function is:

f(x)=4x^3-x^2-5x+7

You know that you must evaluate this function for x=2.

Then, to evaluate the function for x=2, you need to substitute this value into the given function and simplify it.

Therefore, you get:

f(x)=4x^3-x^2-5x+7\\f(2)=4(2)^3-(2)^2-5(2)+7\\f(2)=4(8)-(4)-10+7\\f(2)=32-4-10+7\\f(2)=25

So, the answer is: f(2)=25

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3 years ago
Can you help me solve systems of equations by elimination step by step<br> 6x+y=15<br> -7x-2y=-10
Anna71 [15]

Answer:   (4, -9)

<u>Step-by-step explanation:</u>

Use elimination method.  Manipulate one (or both) equations to eliminate one of the variables and solve for the remaining variable.  <em>I will be eliminating y</em>

6x +  y =  15    → 2(6x +  y =  15)   →   12x + 2y = 30

-7x - 2y = -10   → 1(-7x + 2y = -10)   →  <u> -7x - 2y = -10</u>

                                                             5x        = 20

                                                               x         =  4

Next, replace "x" with "4" into either equation and solve for y.

6(4) + y = 15

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<u>Check:</u>

Plug in x = 4 and y = -9 into the other equation to verify it makes a true statement.

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-7(4) - 2(-9) = -10

-28  -   -18  = -10

-28  +  18 = -10

       -10    =  -10  \checkmark

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Work is force times distance. Note that the only work done here is in the direction opposed to gravity, or if you prefer the change in height times the weight...

W=3sin20(8*9.8)

W≈80.44 J
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