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scoundrel [369]
3 years ago
11

(Please respond quickly!)

Mathematics
2 answers:
Mumz [18]3 years ago
6 0

Step-by-step explanation:

A. x-7+7=10-7

x=17

B. 2x+3-3=19-3

2x/2=16/2

x=8

C.3*x+3*4=6

3x+12=6

3x+12-12=6-12

3x/3=-6/3

x=-2

D. 4x+7=2x+11

4x-2x=11-7

2x/2=4/2

x=2

Scilla [17]3 years ago
5 0

Answer

3,16/2,

Step-by-step explanation:

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The quotient of a number, x, decreased by 4 and 7 is less than or equal to 2 or greater than or equal to 8. What are the possibl
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4 years ago
Find the number of ways of arranging the numbers
Doss [256]

First of all, note that all integers are either 0,1, or 2 modulo 3 (if you're not familiar with this terminology, it means that every integer is either a multiple of 3, or it is 1 or 2 away from a multiple of 3).

So, we can think of our numbers as

\begin{array}{c|c}x&x\mod 3\\0&0\\1&1\\2&2\\3&0\\4&1\\5&2\\6&0\\7&1\\8&2\\9&0\end{array}

In order to make sure that the sum of any three adjacent numbers is divisible by 3, we have to make sure that any group of 3 three adjacent numbers contains a 0, a 1 and a 2. This is possible only if we arrange our 9 numbers in 3 groups of 3 numbers containing 0,1 and 2 exactly once, repeating always the same pattern.

For example, we could arrange our numbers following the pattern

0,1,2,0,1,2,0,1,2

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We have 3!=6 possible patterns. Suppose for example that we choose the pattern

0,1,2,0,1,2,0,1,2

One possible way of following this pattern would be the arrangement

3,1,2,6,4,5,9,7,8

In fact, we substituted every '0' with a multiple of 3 (3, 6 or 9), every '1' with a number 1 away from a multiple of 3 (1, 4 or 7) and every '2' with a number 2 away from a multiple of 3 (2, 5 or 8).

This means that, once we fix a patter, we have 3 choices for the first 3 slots, 2 choices for the next 3 slots, and the final slot will be fixed. So, we have

3\cdot 3\cdot 3\cdot 2 \cdot 2 \cdot 2 = 216

possible ways of following a fixed pattern. Since the number of patterns was 6, we have

216\cdot 6 = 1296

possible arrangements.

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3 years ago
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