Answer:
C) 0 ≤ x ≤ 25
Step-by-step explanation:
We are supposed to find a reasonable constraint so that the function is at least 300 i.e. the value of x at which f(x) is greater or equal to 300
A)x ≥ 0
Refer the graph
At x = 0
f(x)=300
On increasing the value of x , f(x) increases but at x = 12 it starts decreasing
So, x ≥ 0 can also have f(x)<300
So, Option A is wrong
B)−5 ≤ x ≤ 30
At x = -5
f(x) = 100
So, Option B is wrong since we require f(x) is greater or equal to 300
c)0 ≤ x ≤ 25
At x = 0
f(x)=300
At x = 12 , it starts decreasing
At x = 25
f(x)=300
So, The value of f(x) is at least 300 when 0 ≤ x ≤ 25
D)All real numbers
At x = 30
f(x)=0
But we require f(x) greater or equal to 300
Hence Option C is true
I would say 504 basing it off of converting 2/3 into 4/6 and used sets of 84 to each be 1/6
The slope is gonna be 3
the equation will be y=3x+20
The volume of the rectangular prism is
Where:
B is the base area
H is the height
Since the base area is 160 feet^2
Since the volume is 1360 feet^3
Substitute them in the rule above
Divide both sides by 160 to find H
The height of the container is 8.5 feet
Answer:3x
Step-by-step explanation:
If 2x+y=2y−x, then the value of y in terms of x can be
3x
