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3 years ago

8

Please help me with number 7.

1 answer:

Neko [114]3 years ago

6 0

7a expression: 12 + (- 1) + (- 1) + 3
7b evaluate: 13 Solving:((12 + -1 = 11) + (-1 + 3 = 2) (11 + 2 = 13))
7c: At the end of the three days, the value of the stock was $13.

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Can someone help me please?

Mars2501 [29]

Answer:

Answer below

Step-by-step explanation:

Point D: (-6,-1)

Point C: (-3,0)

Point B: (-3,6)

Point A: (0,0)

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2 years ago

Which graph shows a line with a slope of 2 and a y-intercept of 0?

Vikki [24]

Answer: C

Step-by-step explanation: graph C’s slope is 2x and has a y intercept of 0. This is the only right answer because A does not have a y intercept of 0, B’s slope is -2x, and D is not a function.

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2 years ago

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A boy, flying a kite, holds the string 5 feet above the ground and plays out string at 2 ft./sec. as the kite moves horizontally

yKpoI14uk [10]

Answer:x = 75

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by using Pythagorean Theorem, we find x

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4 0

2 years ago

What is the deposit of $40

Sliva [168]

The integer form is + 40.

The integer form is - 25

<h3>What is an integer?</h3>

An integer is a whole number from the set of negative, non-negative, and positive numbers.

Therefore, integers can be written without fractional components.

Hence, integers may include negative or positive numbers . Examples are -1, 2, 5, -8, 9 and many more.

A deposit of 40 dollars means gain. Therefore, the integer form is + 40.

A loss of 25 pounds mean loss. Therefore, the integer form is - 25

learn more on integers here:brainly.com/question/15267155

#SPJ1

4 0

1 year ago

Look at pic and answer pls

PtichkaEL [24]

(a) $x^{-5}$

(b) $3x^{-7}$

(c) $$\frac{4}{3}x^4$

Solution:

To write each of the given expression in the form $ax^n$ :

(a) $\frac{x^3}{x^8}$

Using exponential rule: $\frac{a^x}{a^y}=a^{x-y}$

$$\frac{x^3}{x^8}=x^{3-8}$

$$\frac{x^3}{x^8}=x^{-5}$

(b) $\frac{6x}{2x^8}$

Divide numerator and denominator by the common factor 2, we get

$$\frac{6x}{2x^8}=\frac{3x}{x^8}$

Using exponential rule: $\frac{a^x}{a^y}=a^{x-y}$

$$=3x^{1-8}$

$$\frac{6x}{2x^8} =3x^{-7}$

(c) $\frac{28x^6}{21x^2}$

Divide numerator and denominator by the common factor 7, we get

$$\frac{28x^6}{21x^2}=\frac{4x^6}{3x^2}$

Using exponential rule: $\frac{a^x}{a^y}=a^{x-y}$

$$=\frac{4}{3}x^{6-2}$

$$\frac{28x^6}{21x^2}=\frac{4}{3}x^4$

8 0

3 years ago