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mr_godi [17]
3 years ago
9

72+4-14d=36 I need to show my work.

Mathematics
1 answer:
STALIN [3.7K]3 years ago
3 0

Answer:d=20/7

Step-by-step explanation:

72+4−14d=36

72+4+−14d=36

(−14d)+(72+4)=36(Combine Like Terms)

−14d+76=36

−14d+76=36

Step 2: Subtract 76 from both sides.

−14d+76−76=36−76

−14d=−40

Step 3: Divide both sides by -14.

−14d

−14

=

−40

−14

d=

20

7

Answer:

d=

20

7

 

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lisabon 2012 [21]

Given the following functions below,

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Factorising the denominators of both functions,

Factorising the denominator of f(x),

\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}=\frac{x+12}{x^2+6x-2x-12}=\frac{x+12}{x(x+6)-2(x+6)}=\frac{x+12}{(x-2)(x+6)} \\ f(x)=\frac{x+12}{(x-2)(x+6)} \end{gathered}

Factorising the denominator of g(x),

\begin{gathered} g(x)=\frac{4x^2-16x+16}{4x+48}=\frac{4(x^2-4x+4)}{4(x+12)} \\ \text{Cancel out 4 from both numerator and denominator} \\ g(x)=\frac{x^2-4x+4}{x+12}=\frac{x^2-2x-2x+4}{x+12}=\frac{x(x-2)-2(x-2)}{x+12}=\frac{(x-2)^2}{x+12} \\ g(x)=\frac{(x-2)^2}{x+12} \end{gathered}

Multiplying both functions,

undefined

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Answer:

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Step-by-step explanation:

<u><em>Explanation:-</em></u>

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The average velocity of the function over the given interval

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now integrating

                           =   \frac{1}{3}( \int\limits^7_4 {(\frac{3}{x} )} \, dx-2\int\limits^7_4 {1} \, dx )

                           = \frac{1}{3} (3 (log x) - 2 x )_{4} ^{7}

                        =   \frac{1}{3}( (3 (log 7) - 14 )-(3 log 4 -8))

by using formulas

                 log a-log b = log(a/b)

  on simplification , we get                  

                 = \frac{1}{3}( (3 (log 7) -3 log 4 ) - \frac{1}{3} (6)

                = log(\frac{7}{4} ) -2

Average velocity of the function over the given interval

              =  log(\frac{7}{4} ) -2

 

 

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