A student group at NAU collected information from a local dine in resturant indicating the tip amount left by customers over the
course of a two year period. The tip amounts were roughly normally distributed with a mean of $7.84 and a standard deviation of $2.60
1 answer:
Answer:
The desired range will be "($ 2.64, $ 13.04)".
Step-by-step explanation:
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The given values are:
Mean
= $ 7.84
Standard deviation
= $ 2.60
Those are established by empirical rule whether 95% including its values cheat throughout two standard deviations of such the mean, for something like a roughly normal distribution results.
Thus, the range of values which might absorb 95% of all sums will be:
=
On putting the estimated values, we get
=
=
=
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