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faltersainse [42]
3 years ago
8

A student group at NAU collected information from a local dine in resturant indicating the tip amount left by customers over the

course of a two year period. The tip amounts were roughly normally distributed with a mean of $7.84 and a standard deviation of $2.60

Mathematics
1 answer:
STatiana [176]3 years ago
3 0

Answer:

The desired range will be "($ 2.64, $ 13.04)".

Step-by-step explanation:

The query given seems to be missing. Kindly check find the entire questions attachment.

The given values are:

Mean

= $ 7.84

Standard deviation

= $ 2.60

Those are established by empirical rule whether 95% including its values cheat throughout two standard deviations of such the mean, for something like a roughly normal distribution results.

Thus, the range of values which might absorb 95% of all sums will be:

= (Mean - 2\times Standard \deviation, Mean + 2\times Standard \ deviation)

On putting the estimated values, we get

= (7.84 - 2\times 2.60, 7.84+ 2\times 2.60)

= (7.84-5.2, 7.84+5.2)

= ($2.64, $ 13.04)

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The next term of the series, 3, 10, 29, 66, 127 is 218.
5 0
3 years ago
Find the coordinates for the midpoint of the segment with endpoints give (3,5) and (-2,0)
Leto [7]

Answer:

The coordinates of the mid-point are :

(\frac{1}{2}, \frac{5}{2})

Step-by-step explanation:

We know that, the coordinates of the mid-point (<em>x</em>, <em>y</em>) of a line segment joining the points (<em>x</em>₁, <em>y</em>₁) and (<em>x</em>₂, <em>y</em>₂) is given by

(x, y) = (\frac{x_{1} +x_{2} }{2},\frac{y_{1}+y_{2} }{2} )

Now, we have the given points as (3, 5) and (-2, 0).

By using the above formula, coordinates of the mid-point (<em>x</em>, <em>y</em>) of the line-segment joining the points (3, 5) and (-2, 0) is given by,

x = \frac{3+(-2)}{2} = \frac{3-2}{2} = \frac{1}{2}

y = \frac{5+0}{2} = \frac{5}{2}

∴ coordinates of the mid-point of the line-segment joining the points (3,5) and (-2,0) is (\frac{1}{2}, \frac{5}{2}).

8 0
3 years ago
Triangle XYZ, with vertices X(-2, 0), Y(-2, -1), and Z(-5, -2), undergoes a transformation to form triangle X′Y′Z′, with vertice
Debora [2.8K]
<h2>Answer with explanation:</h2>

1)

The vertices of X,Y and Z are:

X(-2, 0), Y(-2, -1), and Z(-5, -2)

Now, when X,Y and Z are translated by using the translation transformation:

         (x,y) → (x+6,y-2)

Then we obtain the transformation:    

X(-2, 0) → X′(4, -2)

Y(-2, -1) → Y′(4, -3)

Z(-5, -2) →  Z′(1, -4)

The type of transformation that triangle XYZ undergoes is a translation transformation by the rule:   (x,y) → (x+6,y-2)

2)

Next when we reflect the triangle X'Y'Z' across the x-axis then we obtain X"Y"Z"

Since, the rule that follow on reflecting across x-axis is:

           (x,y) → (x,-y)

Hence, we get:

X′(4, -2) → X″(4, 2)

Y′(4, -3) →  Y″(4, 3)

Z′(1, -4) → Z″(1, 4)

Hence, the type of transformation that triangle X′Y′Z′ undergoes is a reflection transformation (on reflecting across x-axis)

5 0
3 years ago
Suppose that a company claims that its air fresheners last 23 days, on
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Answer:

95 - 23 = 17

Step-by-step explanation:

This is the answer because it is subtracted so that you get the answer

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What is the constant rate of change for the relationship shown in the table?
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Answer:

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Step-by-step explanation:

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