Question

A student group at NAU collected information from a local dine in resturant indicating the tip amount left by customers over the course of a two year period. The tip amounts were roughly normally distributed with a mean of $7.84 and a standard deviation of $2.60

Answer 1

Answer:

The desired range will be "($ 2.64, $ 13.04)".

Step-by-step explanation:

The query given seems to be missing. Kindly check find the entire questions attachment.

The given values are:

Mean

= $ 7.84

Standard deviation

= $ 2.60

Those are established by empirical rule whether 95% including its values cheat throughout two standard deviations of such the mean, for something like a roughly normal distribution results.

Thus, the range of values which might absorb 95% of all sums will be:

= $(Mean - 2\times Standard \deviation, Mean + 2\times Standard \ deviation)$

On putting the estimated values, we get

= $(7.84 - 2\times 2.60, 7.84+ 2\times 2.60)$

= $(7.84-5.2, 7.84+5.2)$

= $( 2.64, 13.04)$