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nata0808 [166]
3 years ago
5

H(x)=2xSquared-2 find H(2N) Does X take on the variable of X here?

Mathematics
1 answer:
inessss [21]3 years ago
5 0
H(x) = 2x^2 - 2
h(2N) = 2(2N)^2 - 2
h(2N) = 2 * 4 N^2 - 2
h(/N) = 8N^2 - 2
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During a lunch period, a survey is done about the students at LCHS with the following results:
Flauer [41]

Answer:

1 in 47.

Step-by-step explanation:

Add all of the outcomes (28 + 2 + 3 + 14).

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1 in 47.

4 0
3 years ago
Luiza is jumping on a trampoline.
lyudmila [28]

Answer:

The second time when Luiza reaches a height of 1.2 m = 2 08 s

Step-by-step explanation:

Complete Question

Luiza is jumping on a trampoline. Ht models her distance above the ground (in m) t seconds after she starts jumping. Here, the angle is entered in radians.

H(t) = -0.6 cos (2pi/2.5)t + 1.5.

What is the second time when Luiza reaches a height of 1.2 m? Round your final answer to the nearest hundredth of a second.

Solution

Luiza is jumping on trampolines and her height above the levelled ground at any time, t, is given as

H(t) = -0.6cos⁡(2π/2.5)t + 1.5

What is t when H = 1.2 m

1.2 = -0.6cos⁡(2π/2.5)t + 1.5

0.6cos⁡(2π/2.5)t = 1.2 - 1.5 = -0.3

Cos (2π/2.5)t = (0.3/0.6) = 0.5

Note that in radians,

Cos (π/3) = 0.5

This is the first time, the second time that cos θ = 0.5 is in the fourth quadrant,

Cos (5π/3) = 0.5

So,

Cos (2π/2.5)t = Cos (5π/3)

(2π/2.5)t = (5π/3)

(2/2.5) × t = (5/3)

t = (5/3) × (2.5/2) = 2.0833333 = 2.08 s to the neareast hundredth of a second.

Hope this Helps!!!

4 0
3 years ago
Solve for X (simplify your answer)​
lora16 [44]

Answer:

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Step-by-step explanation:

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