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SVEN [57.7K]
3 years ago
9

What is this fraction as a decimal?

Mathematics
1 answer:
expeople1 [14]3 years ago
6 0
14.4
hope this helps:)
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What is the answer to this?
OlgaM077 [116]

Answer:

Step-by-step explanation:

Note how this drawing  is symmetrical about a horizontal line drawn halfway between AB and CD and passing through the origin.

Line AB has been subdivided into two equal pieces of length 15, so the length of AB is twice 15, or 30.  Due to the symmetry shown, line CD has the same length:  30.

6 0
3 years ago
Help I dont get what to do
Mars2501 [29]

Answer:

  a/(bxy) if b≠0, x≠0, y≠0, x≠y

Step-by-step explanation:

You have correctly simplified the expression. The conditions placed on both the original and simplified forms are that none of the denominator factors may be zero. The denominator factors are b, x, y, and (x-y).

  \dfrac{a}{bxy}\text{ if $b\ne0;$ $x\ne0;$ $y\ne0;$ $x\ne y$}

6 0
2 years ago
Ten college students were randomly selected. Their grade point averages​ (GPAs) when they entered the program were between 3.5 a
solong [7]

Answer:

The 95% confidence interval for the true slope is (0.03985, 0.14206).

Step-by-step explanation:

For the regression equation:

\hat y=\alpha +\hat \beta x

The (1 - <em>α</em>)% confidence interval for the regression coefficient or slope (\hat \beta ) is:

Ci=\hat \beta \pm t_{\alpha/2, (n-2)}\times SE(\hat \beta )

The regression equation for current GPA (Y) of students based on their GPA's when entering the program (X) is:

\hat Y=3.584756+0.090953 X

The summary of the regression analysis is:

Predictor          Coefficient             SE             t-stat            p-value

Constant             3.584756          0.078183       45.85075      5.66 x 10⁻¹¹

Entering GPA   0.090953          0.022162        4.103932       0.003419

The regression coefficient and standard error are:

\hat \beta = 0.090953\\SE (\hat \beta)=0.022162

The critical value of <em>t</em>  for 95% confidence level and 8 degrees of freedom is:

t_{\alpha/2, n-2}=t_{0.05/2, 10-2}=t_{0.025, 8}=2.306

Compute the 95% confidence interval for (\hat \beta ) as follows:

CI=\hat \beta \pm t_{\alpha/2, (n-2)}\times SE(\hat \beta )\\=0.090953\pm 2.306\times 0.022162\\=0.090953\pm 0.051105572\\=(0.039847428, 0.142058572)\\\approx (0.03985, 0.14206)

Thus, the 95% confidence interval for the true slope is (0.03985, 0.14206).

6 0
3 years ago
What is the value of X?<br> Help please!
anastassius [24]

Answer:

(11√3)/3

Step-by-step explanation:

In order to solve for the variable, you will need to use a trig function. In this case, you will need to use the trig function tangent.

Tan = opposite/adjacent

⇒ Tan 30° = x/11

⇒ 11 · Tan 30° = x

⇒ (11√3)/3 = x

4 0
3 years ago
For questions 8 – 10, answer the questions about tangent-tangent angles.
olchik [2.2K]

Answer:

m(arc ZWY) = 305°

Step-by-step explanation:

8). Formula for the angle formed outside the circle by the intersection of two tangents or two secants is,

Angle formed by two tangents = \frac{1}{2}(\text{Difference of intercepted arcs})

                                                   = \frac{1}{2}(220-140)

                                                   = \frac{1}{2}(80)

                                                   = 40°

9). Following the same rule as above,

Angle formed between two tangents = \frac{1}{2}(\text{Difference of intercepted arcs})

125 = \frac{1}{2}[m(\text{major arc})-m(\text{minor arc})]

250 = [m(\text{arc ZWY})-m(\text{arc ZY})]

250 = m(arc ZWY) - 55

m(arc ZWY) = 305°

Therefore, measure of arc ZWY = 305° will be the answer.

10). m(arc BAC) = \frac{1}{2}([m(\text{arc BDC})-m(\text{arc BC})])

                          = \frac{1}{2}(254-106)

                          = \frac{148}{2}

                          = 74°

4 0
3 years ago
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