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kipiarov [429]
3 years ago
9

a clothing store is raising the prices of all its sweaters by $ 3.00. write an expression that could be used to find the new pri

ce of a sweater that originally cost d dollars?
Mathematics
1 answer:
slega [8]3 years ago
7 0
The expression would be d + 3.

You're raising $3 in every sweaters cost so d is the cost of the sweater and you add 3 to raise $3 in the price.

Hope this helps :)
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Sup community simplify this in 5 mins −5·(−a)·(−a)·(−4)·a thx 4 help!!!!1111!!!1!111
liraira [26]

Answer:

20a³

Step-by-step explanation:

Simply multiply:

-5(-4) = 20

-a(-a)(a) = a²(a) = a³

20a³

6 0
2 years ago
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Dream Loan Bank offers loans. Carrie borrows $10,500 to help start a business. The loan must be repaid at 4.5% simple interest o
MaRussiya [10]

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7 0
2 years ago
A random sample of 100 observations from a quantitative population produced a sample mean of 22.8 and a sample standard deviatio
natima [27]

Answer:

We conclude that the population mean is 24.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 24

Sample mean, \bar{x} = 22.8

Sample size, n = 100

Alpha, α = 0.05

Sample standard deviation, s = 8.3

First, we design the null and the alternate hypothesis

H_{0}: \mu = 24\\H_A: \mu \neq 24

We use Two-tailed z test to perform this hypothesis.

Formula:

z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }

Putting all the values, we have

z_{stat} = \displaystyle\frac{22.8 - 24}{\frac{8.3}{\sqrt{100}} } = -1.44

We calculate the p-value with the help of standard z table.

P-value = 0.1498

Since the p-value is greater than the significance level, we accept the null hypothesis. The population mean is 24.

Now, z_{critical} \text{ at 0.05 level of significance } = \pm 1.96

Since,  the z-statistic lies in the acceptance region which is from -1.96 to +1.96, we accept the null hypothesis and conclude that the population mean is 24.

7 0
3 years ago
Please help me!<br> Find the number x such that f(x) =1
STatiana [176]

Answer:

D

Step-by-step explanation:

We have the piecewise function:

f(x) = \left\{        \begin{array}{ll}            -\frac{1}{2}x-1 & \quad x \leq -2 \\            x & \quad x > -2        \end{array}    \right.

And we want to find x such that f(x)=1.

So, let's substitute 1 for f(x):

1 = \left\{        \begin{array}{ll}            -\frac{1}{2}x-1 & \quad x \leq -2 \\            x & \quad x > -2        \end{array}    \right.

This has two equations. So, we can separate them into two separate cases. Namely:

1=-\frac{1}{2}x-1\text{ or } 1=x

Let's solve for x in each case.

Case I:

We have:

1=-\frac{1}{2}x-1

Add 1 to both sides:

2=-\frac{1}{2}x

Let's cancel out the fraction by multiplying both sides by -2. So:

2(-2)=(-2)\frac{-1}{2}x

The right side cancels:

-4=x\\

Flip:

x=-4

So, x is -4.

Case II:

We have:

1=x

Flip:

x=1

This is the solution for our second case.

So, we have:

x_1=-4\text{ or } x_2=1

Now, can check to see if we have to to remove solution(s) that don't work.

Note that x=-4 is the solution to our first equation.

The first equation is defined only if x is less than -2.

-4 <em>is </em>less than -2. So, x=-4 is indeed a solution.

x=1 is the solution to our second equation.

The second equation is defined only if x is greater than or equal to -2.

1 <em>is</em> greater than or equal to -2. So, x=1 is <em>also </em>a solution.

Therefore, our two solutions are:

x_1=-4\text{ or } x_2=1

Out of our answer choices, we can pick D.

And we're done!

7 0
3 years ago
Evaluate the expression. -3 + (-2)
mart [117]
That's answer exactly is -5
6 0
3 years ago
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