Question

13pts is given NEED ABSOLUTE HELP PLEASE ALGEBRA 1 MATH PLEASE PLEASE HELP WITH MY MATH

Answer 1

Answer:

the slope to the line perpendicular to the original equation is $\frac{8}{3}x$

the slope to the given equation is $\frac{8}{3}x$

i hope this helps!   :)

Step-by-step explanation:

given   8x - 3y = -1

move the 8x over to the other side making the 8x a negative   -3y = -8x -1

divide everything by 3   -y = $-\frac{8}{3}x$$-\frac{1}{3}$

transfer the negative from the y to everything else   y = $\frac{8}{3}x + \frac{1}{3}$

the slope is $\frac{8}{3}x$

pic below to show the lines are the same to all the equations

what is the slope of the line perp. to the original equation?

with every slope in an equation you flip the reg. slope around so you have $-\frac{3}{8}$ to $\frac{8}{3}$