Answer:
Hrmm
Step-by-step explanation:
To answer this item, we combine all terms involving the variable z to only one side of the equation. All else will be placed on the other side of the equation. This is as follows,
-cz + 6z = tz + 83
Transposing,
-cz - tz + 6z = 83
Factoring z out,
z(-c - t + 6) = 83
Dividing the equation such that z will be left on one side of the equation,
<em> z = 83 / (-c - t + 6)</em>
The answer as a mixed number: -2 1/4
the answer as a decimal: -2.25
the answer as an improper fraction: -9/4
Ok so these are the first 3 hope its clear
Our current list has 11!/2!11!/2! arrangements which we must divide into equivalence classes just as before, only this time the classes contain arrangements where only the two As are arranged, following this logic requires us to divide by arrangement of the 2 As giving (11!/2!)/2!=11!/(2!2)(11!/2!)/2!=11!/(2!2).
Repeating the process one last time for equivalence classes for arrangements of only T's leads us to divide the list once again by 2
