Question

L-Lcosθ=v^2/2 solve for L

Answer 1

Answer:

$L=\frac{v^2}{2-2\cos(\theta)}$

Step-by-step explanation:

Solve for $L$ in

$L-L \cos(\theta)=\frac{v^2}{2} \Longrightarrow L(1-\cos(\theta))=\frac{v^2}{2}$

$L=\frac{v^2}{2(1-\cos(\theta))}=\frac{v^2}{2-2\cos(\theta)}$