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mafiozo [28]
4 years ago
13

L-Lcosθ=v^2/2 solve for L

Mathematics
1 answer:
Naya [18.7K]4 years ago
4 0

Answer:

$L=\frac{v^2}{2-2\cos(\theta)}$

Step-by-step explanation:

Solve for L in

$L-L \cos(\theta)=\frac{v^2}{2} \Longrightarrow L(1-\cos(\theta))=\frac{v^2}{2}$

$L=\frac{v^2}{2(1-\cos(\theta))}=\frac{v^2}{2-2\cos(\theta)}$

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