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inysia [295]
3 years ago
13

PLZ HELP WILL MARK AS BRAINLEST 30 POINTS

Mathematics
1 answer:
balandron [24]3 years ago
6 0

area of circle : πr²

area of sector : x/360 x πr²

firstly, you have to find. the area of a circle

π(6)² = 36π

then, find the area of the of the sector (not in the shape)

90°/360° x π(6)² = 12π

[90° is given)]

next, you just minus the total and the area of the sector.

36(3.14) - 12(3.14) = 75.36 units

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sin(a - b) = sin(a) cos(b) - sin(b) cos(a)

Notice that adding the first two together, and subtract the last from the third, we get two more identities:

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Let a = 4x and b = x. Then

cos(5x) + cos(3x) = 2 cos(4x) cos(x)

sin(5x) - sin(3x) = 2 sin(x) cos(4x)

Now,

-\dfrac{\cos(3x)+\cos(5x)}{\sin(3x)-\sin(5x)}=\dfrac{\cos(5x)+\cos(3x)}{\sin(5x)-\sin(3x)}=\dfrac{2\cos(4x)\cos x}{2\sin x\cos(4x)}=\dfrac{\cos x}{\sin x}=\cot x

as required.

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4 years ago
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