(-2,2)
i just did my homework with the same question
Answer:
- domain: all terms are defined for <em>all real numbers</em>
- solution: x = 6
Step-by-step explanation:
Rewrite the equation as a single exponential. After taking the log, the solution becomes obvious.

Answer:
Add four to each sum
Step-by-step explanation:
32, 36, 40
32 + 4 = 36
36 + 4 = 40
Rule: Add four to each sum
Hope this helped!
(Let me know if I got something wrong!)
Answer:
its not showing up
Step-by-step explanation:
Ik one of them.. x = 6 to 000