Mars has two moons. How many objects would cause tides on Mars, if it had water

Biology

2 answers:

Gemiola [76]3 years ago

8 0

Both of the moon and The Sun

<h3>Explanation : </h3>

Mars is known as the fourth closest planet from the Sun. It have two satellite named Phobos and Deimos. Actually, the both of Mars's moon is just an asteroid that trapped by Mars's gravity. So, can the both of its moon make a tidal waves if Mars had water ? Yes, it can if we calculate the Newtonian Gravity Forces.

We know that :

mp = mass of Phobos = 1.06 × 10^16 kg
md = mass of Deimos = 1,5 × 10^15 kg
mm = mass of Mars = 6,4 × 10^23 kg
rp = radius of Phobos from Mars = 9376 km = 9,376 × 10^6 m
rd = radius of Deimos from Mars = 23463 km = 23,46 × 10^6 m
G = gravity coefisien = 6.67 × 10^-11 N.m^2.kg^-2

So, we can calculate the Phobos force to Mars

$F_p = G \times { \frac{m_m \times m_p}{r^{2}}} \\ F_p = 6.67 × 10^{-11}\times {\frac{6.4 \times 10^{23} \times 1.5 \times 10^{15}}{(9.376 × 10^6)^{2}}} \\ F_p = \frac{6.67 \times 6.4 \times 1.5 \times {10}^{ - 11 + 23 + 15} }{\times {10}^{12} } \\ F_p = \frac{45.04 \times {10}^{28} }{87.9 \times {10}^{12} } \\ F_p= 0.512 \times {10}^{16} = 5.12 \times {10}^{15} N$

We can calculate the Deimos force to Mars

$F_d = G \times { \frac{m_m \times m_d}{r^{2}}} \\ F_d = 6.67 × 10^{-11}\times {\frac{6.4 \times 10^{23} \times 1.06 \times 10^{16}}{(23.46 × 10^6)^{2}}} \\ F_d = \frac{6.67 \times 6.4 \times 1.5 \times {10}^{ - 11 + 23 + 15} }{550.37 \times {10}^{12} } \\ F_d = \frac{64.03\times {10}^{27} }{550.37 \times {10}^{12} } \\ F_d= 0.116 \times {10}^{15} = 1.16 \times {10}^{14} N$