When it get smashes hard on the ground.
Answer:
Uno de los progenitores es heterocigoto para color naranja (Nn) y el otro parental es homocigoto recesivo para gris (nn). Al haber una cruza entre un homocigoto recesivo y un heterocigoto, la 50% de la progenie expresa color naranja (Nn), mientras que el otro 50% expresa color gris (nn).
Explanation:
<u>Datos disponibles:</u>
- Cruce entre peces naranjas y peces grises
- 50% de la F1 son peces grises
- Naranja dominante sobre gris
Podemos nombrar el alelo dominante para color naranja <em>N</em>, y al alelo recesivo para color gris <em>n</em>.
Para que en un cruce entre dos fenotipos distintos, el 50% de la primer camada exprese uno de estos fenotipos, entonces uno de los parentales debe ser heterocigoto, mientras que el otro parental debe ser homocigoto recesivo. De esta forma 50% de la primera generación expresara uno de los fenotipos, mientras que el otro 50% expresará el otro fenotipo.
Supongamos que uno de los parentales lleva el genotipo <em>Nn</em>, y el otro parental es <em>nn</em>.
Cruce:
Parental) Nn x nn
Gametas) N n n n
Fenotipos) Naranja Gris
Cuadro de Punnett) N n
n Nn nn
n Nn nn
F1) 2/4 = 1/2 = 50% de la progenie tendrá genotipo heterocigoto, Nn
2/4 = 1/2 = 50% de la progenie tendrá genotipo homocigota recesivo,
nn
50% de la progenie será color naranja (Nn)
50% de la progenie será color gris (nn)
C
Explanation:
Molecule C would be least soluble in water because it is not a polar compound/molecule. It also lacks any unit that can combine with water to form a good hydrogen bond.
- The general rule of solubility is that like dissolves likes.
- Polar molecules will only dissolve in polar solvent.
- Water is a polar solvent with hydrogen bonds in them.
- Hydrocarbons typically have weak london dispersion forces between them and they are not polar.
- Other compounds have functional groups that can form hydrogen bond with water.
learn more:
Hydrogen bonding brainly.com/question/10602513
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Answer: Sexual reproduction: rabbits and dolphins.
Asexual reproduction: Strawberry and potato.
Explanation:
- Sexual reproduction is carried out with the participation of germ cells from two stem organisms - female and male, which transfer the properties of the inherited material to the new plant. The main characteristic of sexual reproduction is the division of the relative fusion of male and female sex cells. The end product of this relationship is the creation of an organism that contains the genetic information of both parents.
- Asexual reproduction is a habit that produces an organism identical to the parent organism, and we call this product clones. This form of reproduction does not involve the germ cells and may occur by division or budding. Many types of plants reproduce in this way. So the strawberries are propagated by boils, and the potatoes are buds from the tub
The
correct answer is they filter urea from blood and produce urine.
<span>
Nitrogenous
wastes tend to form toxic ammonia which needs to be removed. Terrestrial
animals must detoxify ammonia by converting it into a relatively nontoxic molecule-urea
(it occurs in the urea cycle). The urea cycle mainly occurs in the liver and the
produced urea is then released into the blood. It travels to the kidneys where
is filtrated and excreted in urine.</span>
