Drawing a conclusion from the graph, the true statement from the option given is <em>Voter turnout in national election years is irregular from 2006 to </em><em>2020</em><em>.</em><em> </em>
Voter turnout in 2006 was 40% while in 2014 it was 35% `; hence, voters were more interested in 2006 than in 2014.
In some of the years given, less than 50% of Americans participated in the polls.
Hence, the true statement is <em>"</em><em>Voter turnout in national election years is irregular from 2006 to </em><em>2020</em><em>"</em><em> </em>
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The least weight of a bag in the top 5 percent of the distribution is; 246
From the complete question below, we are given;
Population mean; μ = 240
Population standard deviation; σ = 3
Z-score formula is;
z = (x' - μ)/σ
- Now, we want to find the least weight in the top 5 of the distribution and as such we will use;
1 - 0.05/2 = 0.025 as significance level
Z-score at significance level of 0.025 is 1.96
Thus;
1.96 = (x' - 240)/3
3 × 1.96 = x' - 240
x' = 240 + 5.88
x' = 245.88
Approximating to a whole number gives;
x' = 246
Complete question is;
A machine is used to fill bags with a popular brand of trail mix. The machine is calibrated so the distribution of the weights of the bags of trail mix is normal, with mean 240 grams and standard deviation 3 grams. Of the following, which is the least weight of a bag in the top 5 percent of the distribution?
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<span>The Aspire test is taken by students in: third through tenth grade.</span>
10 images per day. Since it can receive 3 mb per second for 11 hours a day, that’s up to 118,800 megabits it can receive in one day. By multiplying the amount of gigabits in a typical picture (11.2) by the amount of megabits in a gigabit (1024) you get that there’s 11,468.8 megabits in each picture. Lastly, divide the number of megs that the station receives in one day by the amount of megs in a picture, and you get 10 and some change, therefore it can receive up to ten FULL pictures in a day
