Question

Kevin and Randy Muise have a jar containing 91 coins, all of which are either quarters or nickels. The total value of the coins in the jar is $14.55. How many of each type of coin do they have?

Answer 1

Q + n = 91
q +n -n =91-n
q= 91-n

.25q +.05n = $14.55
.25(91-n)+.05n = $14.55
22.75-.25n+ .05n= $14.55
22.75 -.20n =14.55
22.75-22.75-.20n=14.55-22.75
-.20n=-8.2
-.20n/-.20n= -8.2/-.20n
n= 41

q + 41 = 91
q +41 -41 = 91-41
q = 50

CHECK
.25(50) + 0.05(41) = $14.55
12.50 + 2.05 = $14.55
$14.55 = $14.55