Answer:
C
Step-by-step explanation:
Given:

Changing the division to multiplication by taking the reciprocal of the second fraction.

<u>The correct option is C</u>
Answer:
A
Step-by-step explanation:
A is the procedure
5.46 to 3 sig figs means the range is {5.455,5.465} and 17.74 means the range {17.735,17.745}.
p=q²/r has a maximum value when q=5.465 and r=17.735 and a minimum value when 5.455 and r=17.745.
So the range of p is 1.6769 to 1.6840. When we have 2 decimal places we get p=1.68 which accommodates the maximum and minimum values of the range. So 2 decimal places is a suitable degree of accuracy, or we could say 3 significant figures.
Answer:
The absolute number of a number a is written as
|a|
And represents the distance between a and 0 on a number line.
An absolute value equation is an equation that contains an absolute value expression. The equation
|x|=a
Has two solutions x = a and x = -a because both numbers are at the distance a from 0.
To solve an absolute value equation as
|x+7|=14
You begin by making it into two separate equations and then solving them separately.
x+7=14
x+7−7=14−7
x=7
or
x+7=−14
x+7−7=−14−7
x=−21
An absolute value equation has no solution if the absolute value expression equals a negative number since an absolute value can never be negative.
The inequality
|x|<2
Represents the distance between x and 0 that is less than 2
Whereas the inequality
|x|>2
Represents the distance between x and 0 that is greater than 2
You can write an absolute value inequality as a compound inequality.
−2<x<2
This holds true for all absolute value inequalities.
|ax+b|<c,wherec>0
=−c<ax+b<c
|ax+b|>c,wherec>0
=ax+b<−corax+b>c
You can replace > above with ≥ and < with ≤.
When solving an absolute value inequality it's necessary to first isolate the absolute value expression on one side of the inequality before solving the inequality.
Step-by-step explanation:
Hope this helps :)
I can't understand what you wanted with the second question (or if that is even a question), but the answer to the first one is 42.