The correct answer is the Science, Technololy, Engineering and Math career cluster.
All of the five careers that are listed fall into the career cluster that is called Science, Technology, Engineering and Math. People working in this career cluster could work in science labs, design products and systems, or support scientists or mathematicians in their work.
Answer:
#import turtle
import turtle
# set screen
Screen = turtle.Turtle()
# decide colors
cir= ['red','green','blue','yellow','purple']
# decide pensize
turtle.pensize(4)
# Draw star pattern
turtle.penup()
turtle.setpos(-90,30)
turtle.pendown()
for i in range(5):
turtle.pencolor(cir[i])
turtle.forward(200)
turtle.right(144)
turtle.penup()
turtle.setpos(80,-140)
turtle.pendown()
# choose pen color
turtle.pencolor("Black")
# importing turtle module
import turtle
# number of sides
n = 10
# creating instance of turtle
pen = turtle.Turtle()
# loop to draw a side
for i in range(n):
# drawing side of
# length i*10
pen.forward(i * 10)
# changing direction of pen
# by 144 degree in clockwise
pen.right(144)
# closing the instance
turtle.done()
turtle.done()
Explanation:
You could probably make a new account if it’s just the account blocked
1 gallon = 4 quarts
using this information, you can then use simple proportion.
if 1 gallon = 4 quarts
then to find the amount of quarts in 2 and 1/2 gallons, you multiply 2 and 1/2 by 4 which should give you 10 gallons
Answer:
// here is code in C++.
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int x=5,y=2,z=9;
int min;
// find the smallest value and assign to min
// if x is smallest
if(x < y && x < z)
// assign x to min
min=x;
// if y is smallest
else if(y < z)
// assign y to min
min=y;
// if z is smallest
else
// assign z to min
min=z;
// print the smallest
cout<<"smallest value is:"<<min<<endl;
return 0;
}
Explanation:
Declare and initialize variables x=5,y=2 and z=9.Then check if x is less than y and x is less than z, assign value of x to variable "min" .Else if value of y is less than value of z then smallest value is y, assign value of y to "min".Else z will be the smallest value, assign its value to "min".
Output:
smallest value is:2
