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RSB [31]
2 years ago
13

A baker is using two different cake molds. A round mold with diameter 8in and height 2in, and a rectangular mold with dimensions

12in, 8in, and 2in.
a. Find the volume of each cake
b. Which mold contains the most cake? Explain how you know.
c. The cake density is 0.454 ounce per cubic inch and the fair price is $0.20 per ounce. What should be a fair price for each cake?
Mathematics
1 answer:
miv72 [106K]2 years ago
8 0

Answer:   The cake density is 0.454 ounce per cubic inch and the fair price is $0.20 per ounce.  What should be a fair price for each cake?

Step-by-step explanation:The cake density is 0.454 ounce per cubic inch and the fair price is $0.20 per ounce.  What should be a fair price for each cake?

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The frequency distributions of two data sets are shown in the dot plots below.
fredd [130]

Answer:

1st, 4th and 6th statements are true.

Step-by-step explanation:

We have been given two dot-plots and we are asked to select all the true statements about given dot plots.

Let us write all the data points of both dot plots.

Data set 1:  

1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4, 7.

Data set 2:  

1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4.

1. The mean of data set 1 is greater than the mean of data set 2.

Let us find mean of both data sets.

\text{Mean of data set 1}=\frac{1+1+1+1+1+2+2+2+2+2+2+2+2+3+3+3+4+4+7}{19}

\text{Mean of data set 1}=\frac{45}{19}

\text{Mean of data set 1}=2.3684\approx 2.37  

\text{Mean of data set 2}=\frac{1+1+1+1+1+2+2+2+2+2+2+2+2+3+3+3+4+4}{18}

\text{Mean of data set 2}=\frac{38}{18}

\text{Mean of data set 2}=2.11

We can see that mean of data set 1 is greater than mean of data set 2, therefore, 1st statement is true.

2. The mean of data set 1 is equal to the mean of data set 2.

Since mean of data set 1 is greater than mean of data set 2, therefore, 2nd statement is false.

3. The median of data set 1 is greater than the median of data set 2.

Since data set 1 has 19 data points, so median of data set 1 will be value of 10th data set, that is 2.

Our data set 2 has 18 data points, so median of data set 2 will be the average of 9th and 10th data points.

\text{Median of data set 2}=\frac{2+2}{2}

\text{Median of data set 2}=\frac{4}{2}=2

Since median of data set 2 is also 2, therefore, 3rd statement is not true.

4. The median of data set 1 is equal to the median of data set 2.

Since both data set's median is 2, therefore, 4th statement is true.

5. The standard deviation of data set 1 is smaller than the standard deviation of data set 2.

Using online SD calculator we get SD of data set 1 is 1.422 and SD of data set 2 is 0.936. Since 1.422 is greater than 0.936, therefore, 5th statement is false.

6. The data sets have the same interquartile range.


Q_1\text{ of data set 1}=1

Q_3\text{ of data set 1}=3

\text{IQR of data set 1}=3-1=2

Q_1\text{ of data set 2}=1

Q_3\text{ of data set 2}=3

\text{IQR of data set 2}=3-1=2

Since both data set's IQR is 2, therefore, 6th statement is true.

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Write<br> 9,639<br> as a decimal number.<br> 10,000
Lyrx [107]

Answer:

.9639

9.639 * 10^3

Step-by-step explanation:

This question was unclear but this is the closest I understood of.

Hope this helped! :)

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How do you solve for the inequality 4x + 8 &lt; 1+(2x-5).
pishuonlain [190]
Answer:
13 over 2

Step-by-Step equation:

4x + 8<2x - 5
4x - 2x < -5-8
-2x<-13
x>13/2 (13 over 2)
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Given the equation 3x-4y=8, which equation below would cause an infinite solutions system
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Answer:

thers nothig below

Step-by-step explanation:

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