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Bingel [31]
3 years ago
6

If the endpoints of have the coordinates A(9, 8) and B(-1, -2), what is the midpoint of AB

Mathematics
2 answers:
Aleksandr [31]3 years ago
4 0
Hope this helps you .......

mariarad [96]3 years ago
4 0

Answer: The midpoint of line segment AB is,

(4,3)

Step-by-step explanation:

Since, the coordinates of the midpoint of a line segment having the endpoints (x_1,y_1) and (x_2,y_2) are,

(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

Thus, the coordinates of midpoint of the line segment AB having endpoints A(9, 8) and B(-1, -2) are,

(\frac{9+(-1)}{2},\frac{8+(-2)}{2})

=(\frac{9-1}{2}, \frac{8-2}{2})

=(\frac{8}{2}, \frac{6}{2})

=(4,3)

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Step-by-step explanation:

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The school buses at a middle school each hold 38 students. The school has, b, buses.
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8 0
3 years ago
g My Notes Water flows from the bottom of a storage tank at a rate of r(t) = 200 − 4t liters per minute, where 0 ≤ t ≤ 50. Find
Arada [10]

Answer:

4,200 liters

Step-by-step explanation:

The flow rate is given by:

r(t) = 200 - 4t

Integrating the flow rate expression from t=0 to t=30 minutes, yields the total volume that flows out of the tank during that period:

\int\limits^{30}_0 {r(t)} = \int\limits^{30}_0 {(200 - 4t} )\, dt \\V=(200t - 2t^2)|_0^{30}\\V= (200*30 -2*30^2)-(200*0 -2*0^2)\\V=4,200\ liters

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3 0
3 years ago
Harriet rolls a number cube what is the probability that the number cube will land on three or four
makvit [3.9K]
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6 0
3 years ago
How can csc^2-cot^2 = 1?
Softa [21]

ANSWER

By simplifying the left hand side using the Pythagorean Identity.

EXPLANATION

The given identity is

\csc^{2} (x) -  \cot^{2} (x) = 1

Take the left hand side and simplify to get the right hand side.

\csc^{2} (x) -  \cot^{2} (x) =  \frac{1}{\sin^{2} (x)}  - \frac{ \cos^{2} (x)}{\sin^{2} (x)}

Collect LCM for the denominators.

\csc^{2} (x) -  \cot^{2} (x) =  \frac{1 -  \cos^{2} (x)}{\sin^{2} (x)}

Recall the Pythagorean Identity.

\cos^{2} (x) +  \sin^{2} (x) = 1

This implies that:

1 -  \cos^{2} (x) =  \sin^{2} (x)

We substitute this to get,

\csc^{2} (x) -  \cot^{2} (x) =  \frac{\sin^{2} (x)}{\sin^{2} (x)}

\csc^{2} (x) -  \cot^{2} (x) = 1

6 0
2 years ago
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