Please help, I was absent for this day so I don't know how to do this.
1 answer:
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Given:
Slips of paper numbered 1 to 15 are placed in a box.
To find:
The probability that the number picked is either a multiple of 5 or an odd number.
Solution:
We have,
Total outcomes = 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15
No. of total outcomes = 15
Multiple of 5 are 5, 10, 15.
Odd numbers are 1, 3, 5, 7, 9, 11, 13, 15.
Number that are either a multiple of 5 or an odd number are 1, 3, 5, 7, 9, 10, 11, 13, 15.
No. of favorable outcomes = 9
We know that,
Therefore, the probability that the number picked is either a multiple of 5 or an odd number is 0.6.
Answer:
Answer:18+4.5
Step-by-step explanation:
This shape is a triangle with a semicircle connected to it
and this triangle is a right triangle so side A=B
that means the other leg is 6.Knowing that we can solve
The formula for the area of a triangle is (base×height)÷2
so that means 6×6 equals 36 and if you divide that by 2 you get the 18.
Now we will deal with the semicircle. We know that both of the legs are 6 so that means the diameter is 6 and now we solve 6 divided by 2 equals 3 and we will have to square that and we will 9 and since it is a semicircle we have to divide it by 2 and that will give us 4.5 and since we have to express it in terms of pi it will be 4.5(pi) and then we add both of the areas
giving us 18+4.5(pi)
and do you go to RSM