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vesna_86 [32]
4 years ago
5

Using technology, we found that Juan’s investment account can be modeled by the function, C(x) = 3x2 - 2x + 5, in thousands of d

ollars. What was Juan’s initial investment? $5 $10 $5,000 $10,000
Mathematics
2 answers:
lozanna [386]4 years ago
8 0
The value of the initial investment is given when x = 0, so substituting x = 0 into the function, we have

C(0) = 3(0)²-2(0)+5
C(0) = 5

The initial investment is $5
nikklg [1K]4 years ago
5 0

Answer:

The correct option is 3.

Step-by-step explanation:

Juan’s investment account (in thousands of dollars) can be modeled by the function

C(x)=3x^2-2x+5

Put x=0, to find the Juan’s initial investment.

C(0)=3(0)^2-2(0)+5

C(0)=5

Juan’s initial investment is $5 (in thousands). It can be written as $5000.

Therefore the correct option is 3.

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Find a and b such that gcd(a, b) = 14, a > 2000, b > 2000, and the only prime divisors of a and b are 2 and 7.
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a = 2^\alpha.14 \ ,\alpha\geq 8\\b = 7^\delta.14 \ , \delta\geq 3

Step-by-step explanation:

As 2  and 7 are the only prime divisors of both a and b we know that both can be written as:

a = 2^\alpha . 7^\beta \ , \alpha ,\beta\ \in \mathbb{N}_{0}\\b = 2^\gamma . 7^\delta \ , \gamma ,\delta\ \in \mathbb{N}_{0}\\

Where \mathbb{N}_{0} is the set of all natural numbers adding the zero (careful because this part is important as I'll explain next).

We also know that 14 divides both numbers and that is actually the greatest common divisor between them. So we can rewrite a and b as follows:

a = 2^\alpha . 7^\beta.14 \ , \alpha ,\beta\ \in \mathbb{N}_{0}\\b = 2^\gamma . 7^\delta.14 \ , \gamma ,\delta\ \in \mathbb{N}_{0}\\

Why do I write them like this? Because this way is easier to observe that if \alpha and \gamma were both greater than zero, then 28 would divide both hence 14 wouldn't be their g.c.d.. Likewise, if \beta and \delta were both greater than zero, then 98 would divide both and once again, 14 wouldn't be their g.c.d.

So either of them has to be equal to zero. And then we have that

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