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makkiz [27]
3 years ago
12

3y^2-9x=0 solve for y

Mathematics
1 answer:
Kamila [148]3 years ago
4 0
1

Factor out the common term 3
3(y^2-3x)=0
2 Divide both sides by 3
y^2-3x=0
3 Add 3x to both sides
y^2=3x
4 Take the square root of both sides
y= positive or negative √3x

Hope I helped!
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A $250 item is reduced to $205. Find the percent discount
SOVA2 [1]

Answer:

18%

Step-by-step explanation:

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What is 8 divided by 2.5 (In fraction form)
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8/2.5
 
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4 0
3 years ago
A concrete pillar has the shape of a cylinder. It has a diameter of 8 meters and a height of 9 meters. If concrete costs $87 per
Komok [63]

Answer:

Cost, C = $28410.72

Step-by-step explanation:

We have, a concrete pillar has the shape of a cylinder.

Diameter of pillar is 8 m and ts height is 9 m

If concrete costs $87 per cubic meter, it is required to find the concrete cost for the pillar. For this lets find the area of cylindrical shape. So,

A=2\pi rh+2\pi r^2\\\\A=2\times 3.14\times 4\times 9+2\times 3.14\times 4^2\\\\A=326.56\ m^2

The cost of pillar at the rate of $87 per cubic meter will be :

C=326.56\times 87\\\\C=\$28410.72

8 0
3 years ago
According to the last census (2010), the mean number of people per household in the United States is LaTeX: \mu = 2.58 Assume a
Veseljchak [2.6K]

Answer:

P(2.50 < Xbar < 2.66) = 0.046

Step-by-step explanation:

We are given that Population Mean, \mu = 2.58 and Standard deviation, \sigma = 0.75

Also, a random sample (n) of 110 households is taken.

Let Xbar = sample mean household size

The z score probability distribution for sample mean is give by;

             Z = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

So, probability that the sample mean household size is between 2.50 and 2.66 people = P(2.50 < Xbar < 2.66)

P(2.50 < Xbar < 2.66) = P(Xbar < 2.66) - P(Xbar \leq 2.50)

P(Xbar < 2.66) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{2.66-2.78}{\frac{0.75}{\sqrt{110} } } ) = P(Z < -1.68) = 1 - P(Z  1.68)

                                                              = 1 - 0.95352 = 0.04648

P(Xbar \leq 2.50) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } \leq \frac{2.50-2.78}{\frac{0.75}{\sqrt{110} } }  ) = P(Z \leq  -3.92) = 1 - P(Z < 3.92)

                                                              = 1 - 0.99996 = 0.00004  

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7 0
3 years ago
If m∠ATB = 20°, m∠BTD = 72°, and m∠CTD = 38°, what is m∠ATC?
Ber [7]

Answer: m∠ATC = 54°

Step-by-step explanation:

Ok, we know that:

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then we must have that the angle between A and D, is equal to the sum of the angles between A and B, and B and D, or:

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Now, we also know that m∠CTD = 38°

And the angle:

m∠ATC  will be equal to the angle between A and D, minus the angle between C and D, or:

m∠ATC = m∠ATD - m∠CTD = 92° - 38° = 54°

7 0
3 years ago
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