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morpeh [17]
3 years ago
14

A stainless steel patio heater is shaped like a square pyramid. The length of one side of the base is 19.8 inches. The slant hei

ght is 92.8 inches. What is the height of the heater? Round to the nearest tenth of an inch.

Mathematics
1 answer:
Inessa [10]3 years ago
4 0

Answer:

Step-by-step explanation:

You can look at the photo for more information:

Use the pythagorean theorem to solve this problem

height^{2}  = slant height^{2} - half of base diagonal^{2}  

= 92.8^{2} -19.8^{2}

= 8219.8

Then square root it, we have: \sqrt{8219.8} = 90.66

So the height is: 90.66

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Grace has a bag of candy corn with 378 pieces. She wants to divide it equally and give it to 9 friends in smaller bags. How many
borishaifa [10]

Answer:

42 pieces

Step-by-step explanation:

you do 378÷9

then you'll get the answer which is 42 pieces

6 0
3 years ago
3 +17 p + 2 - P<br> Simply each expression by combing like terms
natita [175]
3+17p+2-p
=3+2+17p-p
=5+16p

hope this helps!!
7 0
2 years ago
Please help it's about Phythagorean Theorem! <br> I attached the image
storchak [24]
Pythagorean Theorem is:

c² = a² + b²

Let’s find the values of a and b.

Looking at the image provided in the question we have 2 number already, 70 and 120.

Let’s name the side with length 120 as a, and the side with length 70 as b.

Then we should substitute these values into the Pythagorean Theorem:


c² = 120² + 70²

c² = 14400 + 4900

c² = 19300

Then we should work out the value of c by square rooting both sides:

√c = √19300

c = 138.92444

Therefore the ball would have to be hit a total of 138.92444 units.

If you have to round, that would be 139 units.
8 0
3 years ago
9 inches of ribbon are needed for wrapping each present. How many presents can be wrapped with 6 yards of ribbon?
netineya [11]

Answer:

a total of 24 presents can be wrapped

Step-by-step explanation:

6 x 3 = 18 feet of ribbon

18 x 12 = 216 inches of ribbon

216/9 = 24 presents can be wrapped

3 0
3 years ago
1.- What type of parabola is this?
xz_007 [3.2K]

Answer:

<u>Part 1</u>

<u>Sideways or "horizontal" parabola</u> with a horizontal axis of symmetry.

<u>Part 2</u>

The vertex is the turning point:  (-3, 1)

<u>Part 3</u>

Vertex form of a horizontal parabola:

x=a(y-k)^2+h    

where:

  • (h, k) is the vertex
  • a is some constant
    If a > 0 the parabola opens to the right.
    If a < 0 the parabola opens to the left.

Point on the curve:  (-1, 2)

Substituting the vertex and the found point into the formula and solving for a:

\implies -1=a(2-1)^2-3

\implies -1=a-3

\implies a=2

<u>Part 4</u>

Equation for the given parabola in vertex form:

x=2(y-1)^2-3

Equation in standard form:

x=2y^2-4y-1

4 0
2 years ago
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