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slavikrds [6]
4 years ago
9

PLEASE HELP

Mathematics
2 answers:
stiks02 [169]4 years ago
8 0

The answer is C. Just took the test


egoroff_w [7]4 years ago
4 0
<h2>Answer:</h2>

The system of inequalities has no solution is:

              Option: C

x+3y is less than or equal to 0.5

x+3y is greater than or equal to 2.5

<h2>Step-by-step explanation:</h2>

A.

x+3y is greater than or equal to 0.5  i.e. x+3y ≥ 0.5

x+3y is less than or equal to 2.5 i.e. x+3y ≤ 2.5

Hence, the common region i.e. obtained from the above 2 inequalities is:

        0.5 ≤ x+3y ≤ 2.5

B.

x+3y is greater than or equal to 0.5  i.e. x+3y ≥ 0.5

x+3y is greater than or equal to 2.5 i.e. x+3y ≥ 2.5

Hence, the common region of the two inequalities will be:

                  x+3y ≥ 2.5

C.

x+3y is less than or equal to 0.5  i.e.  x+3y ≤ 0.5

x+3y is greater than or equal to 2.5 x+3y ≥ 2.5

Hence, the intersection of the region obtained by two inequalities will be empty set.

Hence, the system of inequalities is empty.

Also, by the graph attached of option: C. , it could be observed.

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muminat

Answer:

1 , 2 , 3, 4

Step-by-step explanation:

An expression  is a finite combination of symbols that is well-formed according to rules that depend on the context. meaning it has no = sigh

6 0
3 years ago
The perpendicular distance of the point from x axis is 2 units and the perpendicular distance from y axis is 3 units.Write the c
marysya [2.9K]

Answer:

Step-by-step explanation:

Given that :

the  perpendicular distance of the point from x axis = 2 units

the perpendicular distance from y axis is 3 units

The objective is to the write the coordinates of the points if it lies in

(i) | Quadrant  (ii) || Quadrant (iii) ||| Quadrant (iv) |v Quadrant

The position of a point in a plane is conveniently specified by the distances fro two perpendicular lines.The lines are called the x-axis and y-axis and their [point of intersection is called the origin.

The perpendicular distance from the y-axis is called the x- coordinate or abscissa and the perpendicular distance from x-axis is called the y-coordinate or ordinate,The  coordinate form an ordered pair with the abscissa written as first.

With that be said, So In the given question,

the  perpendicular distance of the point from x axis = 2 units

y coordinate = ±2

the perpendicular distance from y axis is 3 units

x coordinate = ±3

The ordered pair of the coordinates = ( ±3, ±2)

Therefore;

in | quadrant ; we have (3,2)   where  x and y are both on the positive axis

in || quadrant ; we have (-3,2)   x is on the negative axis and y is on the positive axis

In ||| quadrant ; we have (-3. -2) both x and y are on the negative axis

In |v quadrant ; we have ( 3, -2)  x is on the positive axis and y is on the negative axis.

5 0
4 years ago
X - 8 ≤ 4 or 2x + 3 &gt; 9<br> step by step pls
Alchen [17]

Answer:

x - 8 ≤ 4

  +8    +8                         Add eight to both sides of the equation.

X≤12

2x + 3 > 9

     -3     -3                        Subtract three from both sides

2x>6                                  Divide both sides by 2

x>3

Hope this helps!

Have an amazing day/night!

3 0
3 years ago
The circle below is centered at (4, -1) and has a radius of 3. What is its
denis23 [38]

Answer:

Answers C and D are proably missing the y term.  I'll assume they are:

C. (x-4)² + (y-1)² = 9

D. (x-4)² + (y-1)² = 3

A, is the equation that produces the drawn circle.

Step-by-step explanation:

See the attached image for explanation.

6 0
2 years ago
Is the answer to 8+7+12÷3 2
nordsb [41]
Is the last number together??
5 0
4 years ago
Read 2 more answers
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