Step-by-step explanation:
A.
Null hypothesis
H0: σ1² ≤ σ2²
Alternative hypothesis
H1: σ1² > σ2²
We have level of significance = 0.01
Test statistic
F = S1²/S2²
= 170²/100²
= 28900/10000
F = 2.89
Df = degrees of freedom
Df1 = n1 - 1
= 26-1
= 25
Df2 = n2 - 1
= 25-1
= 24
B. We get the p value using f distribution
Fdist(2.89,25,24)
P value = 0.0057
The p-value is less than 0.01 so we reject null hypothesis.
So we conclude that automobiles that are of 4 years have their variances to be larger In annual repair costs than those that are of 2 years.
Reasonableness: we expect this since 4byears old automobiles are more likely to have more expenses during repair leading to greater variances
Answer:
Final Price = $385.60
You save = $96.40
Step-by-step explanation:
Discount = Original Price x Discount %/100
Discount = 482 × 20/100
Discount = 482 x 0.2
You save = $96.40
Final Price = Original Price - Discount
Final Price = 482 - 96.4
Final Price = $385.60
48 kilo.÷8 months is the correct formula to this answer
Janelle will spend $7.50 because each smoothie costs .75 cents.
We have that
solution is
x <-10 or x>=25
for
x < -10
the solution is the interval (-∞, -10)
and
for
x>=25
the solution is the interval [25,∞)
therefore
the solution for
x <-10 or x>=25
is
(-∞, -10) ∪ [25,∞)
<span>the solution is any value of x less than -10 or greater than or equal to 25</span>