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Papessa [141]
3 years ago
14

Litas softball team won 8 games last month and 10 this month, what was the percent change in game the team won? Was it an increa

se or decrease?
Mathematics
1 answer:
11111nata11111 [884]3 years ago
8 0

Answer:

25% and is an increase

Step-by-step explanation:

Games won last month=eight games

Games won this month=ten games

Change in the number of games won=This month- Last month=10-8= 2 games

Percentage change in games won=100*change/original games

Numerical percentage change=100*2/8=25%

This is a positive change hence an increase.

Therefore, percentage change in game the team won is 25% and is an increase

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If f(x)=7x-3, what is the value of x when f(x)=1
frosja888 [35]
Set up your equation:
1 = 7x - 3

Add 3 to both sides:
7x = 4

Divide both sides by 7:
x = 4/7

Hope this helps!
3 0
2 years ago
How do i solve 15=16x-11x
lyudmila [28]
You need to isolate x, which means you need to get it alone. 16x and 11x are like terms because they both have an x, do subtract them. 16-11=5. So 15 = 5x

Then to turn 5x into x, divide by five. This is because 5/5 is 1, and 1x is x. Divide both sides, so

X = 3
8 0
2 years ago
The mean time required to repair breakdowns of a certain copying machine is 93 minutes. The company which manufactures the machi
Sonja [21]

Answer:

t=\frac{88.8-93}{\frac{26.6}{\sqrt{73}}}=-1.349    

p_v =P(t_{(72)}  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, and we can't concluce that the true mean is less than 93 min at 5% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=88.8 represent the sample mean

s=26.6 represent the sample standard deviation for the sample  

n=73 sample size  

\mu_o =93 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean i lower than 93 min, the system of hypothesis would be:  

Null hypothesis:\mu \geq 93  

Alternative hypothesis:\mu < 93  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{88.8-93}{\frac{26.6}{\sqrt{73}}}=-1.349    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=73-1=72  

Since is a one side test the p value would be:  

p_v =P(t_{(72)}  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, and we can't concluce that the true mean is less than 93 min at 5% of signficance.  

5 0
2 years ago
What are the new vertices of quadrilateral ABCD if the quadrilateral is reflected across the x-axis?
Alecsey [184]

Answer:

C.

Step-by-step explanation:

8 0
2 years ago
Steve sold 252 fruit baskets for a school fundraiser. Evie sold 25 fruit baskets for each 100 baskets that Steve sold. How many
Lelechka [254]

Answer:

63 baskets

Step-by-step explanation:

Given data,

Steve sold = 252 baskets

Evie sold = 25 fruit basket for each 100 basket sold by Steve

So, Evie is selling 25% of baskets sold by Steve.

We can calculate the total number of basket sold by Evie by using following formula,

Evie total basket sold = Percent sold by Evie × Basket sold by Steve

By putting the value, we get

Evie total basket sold = 25% × 252

= 63 baskets

4 0
2 years ago
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