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Papessa [141]
3 years ago
14

Litas softball team won 8 games last month and 10 this month, what was the percent change in game the team won? Was it an increa

se or decrease?
Mathematics
1 answer:
11111nata11111 [884]3 years ago
8 0

Answer:

25% and is an increase

Step-by-step explanation:

Games won last month=eight games

Games won this month=ten games

Change in the number of games won=This month- Last month=10-8= 2 games

Percentage change in games won=100*change/original games

Numerical percentage change=100*2/8=25%

This is a positive change hence an increase.

Therefore, percentage change in game the team won is 25% and is an increase

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Suppose a principal amount of $2079 were invested into a simple interest account that pays an annual rate of 2.31% then the amou
Anna35 [415]

Answer:

The amount of interest earned at the end of 14 years would be $672.3486

Step-by-step explanation:

This is a simple interest problem.

The simple interest formula is given by:

E = P*I*t

In which E are the earnings, P is the principal(the initial amount of money), I is the interest rate(yearly, as a decimal) and t is the time.

In this problem, we have that:

P = 2079, I = 0.0231, t = 14

So

E = 2079*0.0231*14 = 672.3486

The amount of interest earned at the end of 14 years would be $672.3486

4 0
2 years ago
Find x in the following triangle pls solve it fast!! Correct answer will get brainliest!!!!
neonofarm [45]

Answer:

c=26

Step-by-step explanation:

So you would use the formula a^2+b^2=c^2

10^2+24^2=c^2

100+576=c^2

C^2=676

c=26

4 0
3 years ago
A line segment is drawn from (1, 9) to (4, 9) on a coordinate grid.
ivanzaharov [21]
D :)
Because the y values are the same, all we need to take into account is the difference in the length of the x values. 
5 0
2 years ago
a spherical balloon is deflated at a rate of 256pi/3 cm^3/sec. at what rate is the radius of the balloon changing when the radiu
Hunter-Best [27]
What you need to look for is \frac { dr }{ dt } when r=8.

Now:

Volume\quad of\quad a\quad sphere:\\ \\ V=\frac { 4 }{ 3 } \pi { r }^{ 3 }

\therefore \quad \frac { dV }{ dr } =\frac { 4 }{ 3 } \pi \cdot 3{ r }^{ 2 }=4\pi { r }^{ 2 }\\ \\ \therefore \quad \frac { dr }{ dV } =\frac { 1 }{ \frac { dV }{ dr }  } =\frac { 1 }{ 4\pi { r }^{ 2 } }

And:\\ \\ \frac { dV }{ dt } =-\frac { 256\pi  }{ 3 } \\ \\ Therefore:\\ \\ \frac { dr }{ dt } =\frac { dr }{ dV } \cdot \frac { dV }{ dt }

\\ \\ =\frac { 1 }{ 4\pi { r }^{ 2 } } \cdot -\frac { 256\pi  }{ 3 } \\ \\ =-\frac { 256 }{ 12 } \cdot \frac { \pi  }{ \pi  } \cdot \frac { 1 }{ { r }^{ 2 } }

\\ \\ =-\frac { 64 }{ 3{ r }^{ 2 } } \\ \\ When\quad r=8,\\ \\ \frac { dr }{ dt } =-\frac { 64 }{ 3\cdot { 8 }^{ 2 } } =-\frac { 1 }{ 3 } \\ \\ Answer:\quad -\frac { 1 }{ 3 } \quad cm/sec
3 0
3 years ago
Josiah invests $360 into an account that accrues 3% interest annually. Assuming no deposits or withdrawals are made, which equat
vlabodo [156]

Answer:

y = 360(1.03)x

Step-by-step explanation:

F = P x (1 + i)^n

F is the future worth, P is the present worth, I will be the interest rate, and n is the number of years. F = ($360)(1.03)^x

The principal amount of the money = $360

Annual rate of interest = 3%

Thus, the amount after x years which is increased by 3%.

Since, this amount represented by y,

The required equation that represents the amount of money in Josiah’s  account, y, after x years is, = 360(1+\frac{3}{100} )^x\\ = 360(1+0.03 )^x\\ = 360(1.03 )^x

This amount represented by y,

Therefore, the required equation that represents the amount of money in Josiah’s account, y, after x years is,

y = 360(1.03 )^x

Hope this helps you!

Have a nice evening! ;)

5 0
3 years ago
Read 2 more answers
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