Will mark as BRAINLIEST

Mathematics

2 answers:

DedPeter [7]3 years ago

8 0

Answer:

B and E

Step-by-step explanation:

The quadrilaterals cannot be placed such that each occupies one-quarter of the circle because the vertices of parallelogram 1 do not form right angles.

The quadrilaterals cannot be placed such that each occupies one-quarter of the circle because the vertices of parallelogram 4 do not form right angles.

Anon25 [30]3 years ago

7 0

Answer:

B and E

Step-by-step explanation:

B. The quadrilaterals cannot be placed such that each occupies one-quarter of the circle because the vertices of parallelogram 1 do not form right angles.

E. The quadrilaterals cannot be placed such that each occupies one-quarter of the circle because the vertices of parallelogram 4 do not form right angles.

Step-by-step explanation:

hope it helps:3

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a highschool computer club has 15 members . how many different ways can they choose a president and vice president

Nataliya [291]

Answer=210 ways

Okay. I'm not entirely sure this is the BEST way to solve for this answer, but nonetheless, I'll show how I would solve the equation.

First, lets look at the probability of the two options happening. The probability of one of the 15 members becoming president is 1/15. Then, since one student is already being used for the spot of president, the odds of another student becoming vice president is 1/14.

$\frac{1}{15} * \frac{1}{14} = \frac{1}{210}$

From this, we know that there are 210 options for the positions of president and vice president total (since 210 represents the whole).

So they can choose the president and vice president 210 different ways

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