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3 years ago

What is a reasonable estimate for the problem? 3 3/4 x -2/5

2 answers:

7 0

-1.5

By using a calculator, making the mixed numeral 3 3/4=3.75, and making -2/5 a decimal = -0.4, you can now simply multiply:

3.75 x -0.4= -1.5
Remember that a positive and a negative give you a negative answer.

Airida [17]3 years ago

6 0

Answer:

You can not break that down any further if x does not equal anything and the equation is not equal to anything.

Step-by-step explanation:

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Solve. 6−3x=3(8−x) <br> 4 all real numbers −4 no solutions

klio [65]

Yea no solution is your answer

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2 years ago

What is the sum of the polynomials?

ASHA 777 [7]

Answer:

$- 4 {x}^{2} - 11x + 13$

Step-by-step explanation:

$( - {x}^{2} + 9) + ( - 3 {x}^{2} - 11x + 4)$

$- {x}^{2} + 9 - 3 {x}^{2} - 11x + 4$

$- 4 {x}^{2} - 11x + 13$

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1 year ago

The cost C (in millions of dollars) for the federal government to seize p% of an illegal drug as it enters the country is given

erik [133]

Answer:

b for me hehe ok

Step-by-step explanation:

Explanation

3 0

2 years ago

What is the mean of this data set 82,105,247,119,94,202

Kazeer [188]

To find the mean, add the numbers, and divide by the amount of numbers there is.

(82 + 105 + 247 + 119 + 94 + 202)/6

Simplify. Remember to follow PEMDAS. First, add

(849)/6

Next, divide by 6

849/6 = 141.5

141.5 should be your answer

hope this helps

6 0

2 years ago

Read 2 more answers

Find, correct to four decimal places, the length of the curve of intersection of the cylinder 16x2 + y2 = 16 and the plane x + y

Yuri [45]

Let the curve C be the intersection of the cylinder

$16x^2+y^2=16$

and the plane

$x+y+z=1$

The projection of C on to the x-y plane is the ellipse

$16x^2+y^2=16$

To see clearly that this is an ellipse, le us divide through by 16, to get

$\frac{x^2}{1}+ \frac{y^2}{16}=1$

$\frac{x^2}{1^2}+ \frac{y^2}{4^2}=1$ ,

We can write the following parametric equations,

$x=cos(t), y=4sin(t)$

for

$0\le t \le 2\pi$

Since C lies on the plane,

$x+y+z=1$

it must satisfy its equation.

Let us make z the subject first,

$z=1-x-y$

This implies that,

$z=1-sin(t)-4cos(t)$

We can now write the vector equation of C, to obtain,

$r(t)=(cos(t),4sin(t),1-cos(t)-4sin(t))$

The length of the curve of the intersection of the cylinder and the plane is now given by,

$\int\limits^{2\pi}_0 {|r'(t)|} \, dt$

But

$r'(t)=(-sin(t),4cos(t),sin(t)-4cos(t))$

$|r'(t)|=\sqrt{(-sin(t))^2+(4cos(t))^2+(sin(t)-4cos(t))}$

$\int\limits^{2\pi}_0 {\sqrt{2sin^2(t)+32cos(t)-8sin(t)cos(t)} }\, dt=24.08778184$

Therefore the length of the curve of the intersection intersection of the cylinder and the plane is 24.0878 units correct to four decimal places.

6 0

3 years ago