Question

If a stone is thrown down at 170 feet per second from a height of 1,020 feet, its height after t seconds is given by

Answer 1

Step-by-step explanation:

It is given that,

Initial speed of the stone, u = 170 ft/s

It is thrown down from a height of 1020 feet.

We need to its height after t seconds. It can be calculated using second equation of kinematics as follows :

$h=ut-\dfrac{1}{2}gt^2+h_0$

h₀ is initial height, u = -170 ft/s as the stone is throwing down and g = -32ft/s²

Putting values, we get :

$h=-170t-\dfrac{1}{2}\times 32t^2+1020\\\\h=-16t^2-170t+1020$