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3 years ago

(x^2-4x+5)+(7x^2+2x-3)(7x^2+4x-6)-(2x^2-3x+1)add or subtract

1 answer:

8 0

8x^4-2x+2

5x^7x-7

I know you're going to question how I got 7. & the answer is when you have to negatives by each other that turns into a positive and you actually add. Hope this helps!

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How many solutions does the following equation have?

Evgesh-ka [11]

Answer:

no solution

Step-by-step explanation:

There are no values of x that make the equation true.

No solution

6 0

3 years ago

Which statements include two quantities in the real world that are additive inverses?

S_A_V [24]

<h3>Answer :</h3>

There are two statements here, showing quantities in real world which are additive inverse of each other :

2. Noa hiked 2 mi up a mountain trail and then hiked 2 mi down the trail.

here, we can depict going up as +2 miles and going down the trail as -2

4. A hot-air balloon ascends 2000 ft from the ground and then descends 2000 ft.

And here we can assume going up the ground aa + 2000 ft and going down aa - 2000 ft .

6 0

3 years ago

Read 2 more answers

Including 8% sales tax, an inn charges $162 per night. Find

laila [671]

Answer:

$150

Step-by-step explanation:

x + 0.08x = 162

1.08 x = 162

x = 150

6 0

3 years ago

The U.S. Energy Information Administration (US EIA) reported that the average price for a gallon of regular gasoline is $2.94. T

Anit [1.1K]

Answer:

a) 25

b) 67

c) 97

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.96$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample. In this problem, $\sigma = 0.25$

(a) The desired margin of error is $0.10.

This is n when M = 0.1. So

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.1 = 1.96*\frac{0.25}{\sqrt{n}}$

$0.1\sqrt{n} = 1.96*0.25$

$\sqrt{n} = \frac{19.6*0.25}{0.1}$

$(\sqrt{n})^{2} = (\frac{19.6*0.25}{0.1})^{2}$

$n = 24.01$

Rounding up to the nearest whole number, 25.

(b) The desired margin of error is $0.06.

This is n when M = 0.06. So

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.06 = 1.96*\frac{0.25}{\sqrt{n}}$

$0.06\sqrt{n} = 1.96*0.25$

$\sqrt{n} = \frac{19.6*0.25}{0.06}$

$(\sqrt{n})^{2} = (\frac{19.6*0.25}{0.06})^{2}$

$n = 66.7$

Rounding up, 67

(c) The desired margin of error is $0.05.

This is n when M = 0.05. So

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.05 = 1.96*\frac{0.25}{\sqrt{n}}$

$0.05\sqrt{n} = 1.96*0.25$

$\sqrt{n} = \frac{19.6*0.25}{0.05}$

$(\sqrt{n})^{2} = (\frac{19.6*0.25}{0.05})^{2}$

$n = 96.04$

Rounding up, 97

8 0

3 years ago

X=c/r make the r as a subject

kupik [55]

Answer:

r = c/x

Step-by-step explanation:

7 0

3 years ago