Question

X^3+3y-xy' = 0 dy/dx = xy^3-xy

Answer 1

Answer:

dy/dx = xy^3-xy   =

y = ± √2 = ± 1.4142

x  =  0

y  =  0

Step-by-step explanation:

Step  1  : Simplify y/d

Step  2  :  See below

Step  3  :  See below

Pulling out like terms

Trying to factor as a Difference of Squares

Answer:  

y = ± √2 = ± 1.4142

x  =  0

y  =  0

Hope this helps.