X^3+3y-xy' = 0
dy/dx = xy^3-xy
1 answer:
Answer:
dy/dx = xy^3-xy =
y = ± √2 = ± 1.4142
x = 0
y = 0
Step-by-step explanation:
Step 1 : Simplify y/d
Step 2 : See below
Step 3 : See below
Pulling out like terms
Trying to factor as a Difference of Squares
Answer:
y = ± √2 = ± 1.4142
x = 0
y = 0
<em><u>Hope this helps.</u></em>
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